A planet is in a circular orbit of radius R R\,R around a star. The orbital period of the planet is TTT. Which expression gives the magnitude of the centripetal acceleration of the planet?
4π2RT2\frac{4\pi^2 R}{T^2}T24π2R
4πR2T\frac{4\pi R^2}{T}T4πR2
2πRT2\frac{2\pi R}{T^2}T22πR
4π2R2T\frac{4\pi^2 R^2}{T}T4π2R2
245 exam-style questions on CIE IGCSE Physics 1.5 Forces, covering 1.5.1a Forces, resultant force and motion, 1.5.1b Load–extension graphs and the spring constant, 1.5.1c Friction and drag, 1.5.1d Force, mass and acceleration, 1.5.1e Motion in a circular path, 1.5.2a Moment of a force, 1.5.2b Principle of moments and equilibrium, and 1.5.3 Centre of gravity and stability. Each one has a worked solution and a mark scheme showing where the marks go.