A coil is connected to a battery, creating an electromagnet. A permanent bar magnet is suspended next to the right end of the coil, with its North pole (NNN) facing the coil.
Initially, the right end of the coil acts as a South magnetic pole. The battery connections are then reversed, which reverses the direction of current.
How does the suspended bar magnet behave in these two cases?
With the battery as shown: attracted to the coil; with the battery reversed: attracted to the coil
With the battery as shown: attracted to the coil; with the battery reversed: repelled from the coil
With the battery as shown: repelled from the coil; with the battery reversed: attracted to the coil
With the battery as shown: repelled from the coil; with the battery reversed: repelled from the coil
275 exam-style questions on CIE IGCSE Physics 4.5 Electromagnetic effects, covering 4.5.1a Electromagnetic induction, 4.5.1b Direction of an induced e.m.f., 4.5.2 The a.c. generator, 4.5.3a Magnetic effect of a current and its applications, 4.5.3b Strength and direction of the field around wires and solenoids, 4.5.4a Force on a current-carrying conductor, 4.5.4b Force on beams of charged particles, 4.5.5 The d.c. motor, 4.5.6a Construction and operation of a transformer, 4.5.6b Turns ratio and current in a transformer, and 4.5.6c High-voltage transmission of electricity. Each one has a worked solution and a mark scheme showing where the marks go.