A smart tracker is powered by a 1.5 V1.5\text{ V}1.5 V cell. The cell supplies a current of 2.8×10−3 A2.8 \times 10^{-3}\text{ A}2.8×10−3 A (0.0028 A0.0028\text{ A}0.0028 A) for 4.5×105 s4.5 \times 10^5\text{ s}4.5×105 s.
Calculate:
the charge that passes through the cell in this time,
the resistance of the electrical circuit in the tracker,
the output power of the cell.
452 exam-style questions on CIE IGCSE Physics 4.2 Electrical quantities, covering 4.2.1a Positive and negative charge, 4.2.1b Charging by friction and detecting charge, 4.2.1c Electrical conductors and insulators, 4.2.1d Electric fields and electric field patterns, 4.2.2a Electric current, charge and measuring current, 4.2.2b Conduction in metals and the direction of current, 4.2.2c Direct current and alternating current, 4.2.3a Electromotive force, 4.2.3b Potential difference and voltmeters, 4.2.4a Resistance, 4.2.4b Resistance of a metallic wire, 4.2.4c Current–voltage graphs, and 4.2.5 Electrical energy and electrical power. Each one has a worked solution and a mark scheme showing where the marks go.