An engineer measures the potential difference across a resistor and the current through it. Which calculation gives the electrical power of the resistor?
potential difference+current\text{potential difference} + \text{current}potential difference+current
potential difference÷current\text{potential difference} \div \text{current}potential difference÷current
current÷potential difference\text{current} \div \text{potential difference}current÷potential difference
potential difference×current\text{potential difference} \times \text{current}potential difference×current
69 exam-style questions on CIE IGCSE Physics 4.2.5 Electrical energy and electrical power. Each one has a worked solution and a mark scheme showing where the marks go.