A smart tracker is powered by a 1.5 V1.5\text{ V}1.5 V cell. The cell supplies a current of 2.8×10−3 A2.8 \times 10^{-3}\text{ A}2.8×10−3 A (0.0028 A0.0028\text{ A}0.0028 A) for 4.5×105 s4.5 \times 10^5\text{ s}4.5×105 s.
Calculate:
the charge that passes through the cell in this time,
the resistance of the electrical circuit in the tracker,
the output power of the cell.
51 exam-style questions on CIE IGCSE Physics 4.2.2a Electric current, charge and measuring current. Each one has a worked solution and a mark scheme showing where the marks go.