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1.5.1a Forces, resultant force and motion

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Question 48

A skycopter or skydiver is falling through the air. The table below gives the values of the acceleration of the skydiver at various heights above the ground.

height / m200015001000500acceleration / m/s28.55.21.80 \begin{array}{|l|c|c|c|c|} \hline \text{height / m} & 2000 & 1500 & 1000 & 500 \\ \hline \text{acceleration / m/s}^2 & 8.5 & 5.2 & 1.8 & 0 \\ \hline \end{array} height / macceleration / m/s2​20008.5​15005.2​10001.8​5000​​
a.

Describe what is happening, during the descent from 2000 m to 500 m, to: (i) the acceleration of the skydiver, (ii) the speed of the skydiver.

[2]
b.

The acceleration becomes zero at a height of 500 m. Use ideas about forces to suggest why this happens.

[2]
c.

Below a height of 500 m, the skydiver opens a parachute. Further measurements show that the acceleration of the skydiver has a negative value. What does this mean is happening to the speed of the skydiver?

[1]
d.

The skydiver has a mass of 80 kg. Calculate the resultant force on the skydiver at a height of 1500 m.

[2]
Markscheme

1.5.1a Forces, resultant force and motion Questions

  1. IGCSE
  2. /Physics
  3. /1.5.1a Forces, resultant force and motion

183 exam-style questions on CIE IGCSE Physics 1.5.1a Forces, resultant force and motion. Each one has a worked solution and a mark scheme showing where the marks go.

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