33:I[196793,["/_next/static/chunks/34batdc-i3b0_.js?dpl=nogit-1791217996","/_next/static/chunks/2_6olli-sutu3.js?dpl=nogit-1791217996","/_next/static/chunks/0zcakt1-boe_f.js?dpl=nogit-1791217996","/_next/static/chunks/0yuh9obhrf6py.js?dpl=nogit-1791217996","/_next/static/chunks/3mz725-y91ph6.js?dpl=nogit-1791217996","/_next/static/chunks/2x_dbpl3b_l2r.js?dpl=nogit-1791217996","/_next/static/chunks/13_9hjun60hj-.js?dpl=nogit-1791217996","/_next/static/chunks/2bxmml65nu49g.js?dpl=nogit-1791217996","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1791217996","/_next/static/chunks/0d3f1nmeak_z5.js?dpl=nogit-1791217996","/_next/static/chunks/2gjyu-jrwu-fu.js?dpl=nogit-1791217996","/_next/static/chunks/38w1x0vrld4-w.js?dpl=nogit-1791217996","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1791217996","/_next/static/chunks/3kzt2piec6aoa.js?dpl=nogit-1791217996","/_next/static/chunks/19ijf68pshdcn.js?dpl=nogit-1791217996","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1791217996","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1791217996","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1791217996","/_next/static/chunks/10rmxw_yiwj40.js?dpl=nogit-1791217996","/_next/static/chunks/40lyu17d590zu.js?dpl=nogit-1791217996","/_next/static/chunks/2g-t2n9ahs3tn.js?dpl=nogit-1791217996","/_next/static/chunks/1g1suj21ijg7y.js?dpl=nogit-1791217996","/_next/static/chunks/3lz9pr5v38m4h.js?dpl=nogit-1791217996","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1791217996","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1791217996","/_next/static/chunks/2oijhb0tdir9b.js?dpl=nogit-1791217996","/_next/static/chunks/2eanemqjnv2vr.js?dpl=nogit-1791217996","/_next/static/chunks/44nm8-o05iplc.js?dpl=nogit-1791217996","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1791217996","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1791217996","/_next/static/chunks/2r29ujce72_54.js?dpl=nogit-1791217996","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1791217996","/_next/static/chunks/1coblm1-go81_.js?dpl=nogit-1791217996","/_next/static/chunks/0jt4ynafgg-jc.js?dpl=nogit-1791217996","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1791217996","/_next/static/chunks/0qdwqau744_ry.js?dpl=nogit-1791217996","/_next/static/chunks/2eycy5cqzjdqf.js?dpl=nogit-1791217996","/_next/static/chunks/33z1jiacs_jrz.js?dpl=nogit-1791217996","/_next/static/chunks/0w7ow4sfu0tl_.js?dpl=nogit-1791217996","/_next/static/chunks/3it1o0ex-l5qz.js?dpl=nogit-1791217996","/_next/static/chunks/1eyu-5752jh17.js?dpl=nogit-1791217996","/_next/static/chunks/28uw5fp_u1bnm.js?dpl=nogit-1791217996","/_next/static/chunks/3ybwgs28on6c8.js?dpl=nogit-1791217996","/_next/static/chunks/0ixdj_i1afhld.js?dpl=nogit-1791217996","/_next/static/chunks/20_c60cgo1g9g.js?dpl=nogit-1791217996","/_next/static/chunks/075i0tnxt4not.js?dpl=nogit-1791217996","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1791217996","/_next/static/chunks/2ryoj58czm802.js?dpl=nogit-1791217996","/_next/static/chunks/3v6lxgtmi9vqz.js?dpl=nogit-1791217996","/_next/static/chunks/13gj59kzq50t_.js?dpl=nogit-1791217996","/_next/static/chunks/3q5gc8lbwr4b4.js?dpl=nogit-1791217996","/_next/static/chunks/0wl6wuakgnlec.js?dpl=nogit-1791217996","/_next/static/chunks/30w6c7jj-mxyi.js?dpl=nogit-1791217996","/_next/static/chunks/2qk8b2y5gyu_0.js?dpl=nogit-1791217996","/_next/static/chunks/3lwy4_ovl68-o.js?dpl=nogit-1791217996","/_next/static/chunks/1hnuhh5t7cfaj.js?dpl=nogit-1791217996","/_next/static/chunks/36nndwkz7iik3.js?dpl=nogit-1791217996","/_next/static/chunks/24srd-xd1m5z8.js?dpl=nogit-1791217996","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1791217996","/_next/static/chunks/1d7tjnrc0fv5y.js?dpl=nogit-1791217996","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1791217996"],"Gingerbread"] 35:I[647935,["/_next/static/chunks/34batdc-i3b0_.js?dpl=nogit-1791217996","/_next/static/chunks/2_6olli-sutu3.js?dpl=nogit-1791217996","/_next/static/chunks/0zcakt1-boe_f.js?dpl=nogit-1791217996","/_next/static/chunks/0yuh9obhrf6py.js?dpl=nogit-1791217996","/_next/static/chunks/3mz725-y91ph6.js?dpl=nogit-1791217996","/_next/static/chunks/2x_dbpl3b_l2r.js?dpl=nogit-1791217996","/_next/static/chunks/13_9hjun60hj-.js?dpl=nogit-1791217996","/_next/static/chunks/2bxmml65nu49g.js?dpl=nogit-1791217996","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1791217996","/_next/static/chunks/0d3f1nmeak_z5.js?dpl=nogit-1791217996","/_next/static/chunks/2gjyu-jrwu-fu.js?dpl=nogit-1791217996","/_next/static/chunks/38w1x0vrld4-w.js?dpl=nogit-1791217996","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1791217996","/_next/static/chunks/3kzt2piec6aoa.js?dpl=nogit-1791217996","/_next/static/chunks/19ijf68pshdcn.js?dpl=nogit-1791217996","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1791217996","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1791217996","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1791217996","/_next/static/chunks/10rmxw_yiwj40.js?dpl=nogit-1791217996","/_next/static/chunks/40lyu17d590zu.js?dpl=nogit-1791217996","/_next/static/chunks/2g-t2n9ahs3tn.js?dpl=nogit-1791217996","/_next/static/chunks/1g1suj21ijg7y.js?dpl=nogit-1791217996","/_next/static/chunks/3lz9pr5v38m4h.js?dpl=nogit-1791217996","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1791217996","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1791217996","/_next/static/chunks/2oijhb0tdir9b.js?dpl=nogit-1791217996","/_next/static/chunks/2eanemqjnv2vr.js?dpl=nogit-1791217996","/_next/static/chunks/44nm8-o05iplc.js?dpl=nogit-1791217996","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1791217996","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1791217996","/_next/static/chunks/2r29ujce72_54.js?dpl=nogit-1791217996","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1791217996","/_next/static/chunks/1coblm1-go81_.js?dpl=nogit-1791217996","/_next/static/chunks/0jt4ynafgg-jc.js?dpl=nogit-1791217996","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1791217996","/_next/static/chunks/0qdwqau744_ry.js?dpl=nogit-1791217996","/_next/static/chunks/2eycy5cqzjdqf.js?dpl=nogit-1791217996","/_next/static/chunks/33z1jiacs_jrz.js?dpl=nogit-1791217996","/_next/static/chunks/0w7ow4sfu0tl_.js?dpl=nogit-1791217996","/_next/static/chunks/3it1o0ex-l5qz.js?dpl=nogit-1791217996","/_next/static/chunks/1eyu-5752jh17.js?dpl=nogit-1791217996","/_next/static/chunks/28uw5fp_u1bnm.js?dpl=nogit-1791217996","/_next/static/chunks/3ybwgs28on6c8.js?dpl=nogit-1791217996","/_next/static/chunks/0ixdj_i1afhld.js?dpl=nogit-1791217996","/_next/static/chunks/20_c60cgo1g9g.js?dpl=nogit-1791217996","/_next/static/chunks/075i0tnxt4not.js?dpl=nogit-1791217996","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1791217996","/_next/static/chunks/2ryoj58czm802.js?dpl=nogit-1791217996","/_next/static/chunks/3v6lxgtmi9vqz.js?dpl=nogit-1791217996","/_next/static/chunks/13gj59kzq50t_.js?dpl=nogit-1791217996","/_next/static/chunks/3q5gc8lbwr4b4.js?dpl=nogit-1791217996","/_next/static/chunks/0wl6wuakgnlec.js?dpl=nogit-1791217996","/_next/static/chunks/30w6c7jj-mxyi.js?dpl=nogit-1791217996","/_next/static/chunks/2qk8b2y5gyu_0.js?dpl=nogit-1791217996","/_next/static/chunks/3lwy4_ovl68-o.js?dpl=nogit-1791217996","/_next/static/chunks/1hnuhh5t7cfaj.js?dpl=nogit-1791217996","/_next/static/chunks/36nndwkz7iik3.js?dpl=nogit-1791217996","/_next/static/chunks/24srd-xd1m5z8.js?dpl=nogit-1791217996","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1791217996","/_next/static/chunks/1d7tjnrc0fv5y.js?dpl=nogit-1791217996","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1791217996"],"RecordResourceResume"] 36:I[830476,["/_next/static/chunks/34batdc-i3b0_.js?dpl=nogit-1791217996","/_next/static/chunks/2_6olli-sutu3.js?dpl=nogit-1791217996","/_next/static/chunks/0zcakt1-boe_f.js?dpl=nogit-1791217996","/_next/static/chunks/0yuh9obhrf6py.js?dpl=nogit-1791217996","/_next/static/chunks/3mz725-y91ph6.js?dpl=nogit-1791217996","/_next/static/chunks/2x_dbpl3b_l2r.js?dpl=nogit-1791217996","/_next/static/chunks/13_9hjun60hj-.js?dpl=nogit-1791217996","/_next/static/chunks/2bxmml65nu49g.js?dpl=nogit-1791217996","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1791217996","/_next/static/chunks/0d3f1nmeak_z5.js?dpl=nogit-1791217996","/_next/static/chunks/2gjyu-jrwu-fu.js?dpl=nogit-1791217996","/_next/static/chunks/38w1x0vrld4-w.js?dpl=nogit-1791217996","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1791217996","/_next/static/chunks/3kzt2piec6aoa.js?dpl=nogit-1791217996","/_next/static/chunks/19ijf68pshdcn.js?dpl=nogit-1791217996","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1791217996","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1791217996","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1791217996","/_next/static/chunks/10rmxw_yiwj40.js?dpl=nogit-1791217996","/_next/static/chunks/40lyu17d590zu.js?dpl=nogit-1791217996","/_next/static/chunks/2g-t2n9ahs3tn.js?dpl=nogit-1791217996","/_next/static/chunks/1g1suj21ijg7y.js?dpl=nogit-1791217996","/_next/static/chunks/3lz9pr5v38m4h.js?dpl=nogit-1791217996","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1791217996","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1791217996","/_next/static/chunks/2oijhb0tdir9b.js?dpl=nogit-1791217996","/_next/static/chunks/2eanemqjnv2vr.js?dpl=nogit-1791217996","/_next/static/chunks/44nm8-o05iplc.js?dpl=nogit-1791217996","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1791217996","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1791217996","/_next/static/chunks/2r29ujce72_54.js?dpl=nogit-1791217996","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1791217996","/_next/static/chunks/1coblm1-go81_.js?dpl=nogit-1791217996","/_next/static/chunks/0jt4ynafgg-jc.js?dpl=nogit-1791217996","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1791217996","/_next/static/chunks/0qdwqau744_ry.js?dpl=nogit-1791217996","/_next/static/chunks/2eycy5cqzjdqf.js?dpl=nogit-1791217996","/_next/static/chunks/33z1jiacs_jrz.js?dpl=nogit-1791217996","/_next/static/chunks/0w7ow4sfu0tl_.js?dpl=nogit-1791217996","/_next/static/chunks/3it1o0ex-l5qz.js?dpl=nogit-1791217996","/_next/static/chunks/1eyu-5752jh17.js?dpl=nogit-1791217996","/_next/static/chunks/28uw5fp_u1bnm.js?dpl=nogit-1791217996","/_next/static/chunks/3ybwgs28on6c8.js?dpl=nogit-1791217996","/_next/static/chunks/0ixdj_i1afhld.js?dpl=nogit-1791217996","/_next/static/chunks/20_c60cgo1g9g.js?dpl=nogit-1791217996","/_next/static/chunks/075i0tnxt4not.js?dpl=nogit-1791217996","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1791217996","/_next/static/chunks/2ryoj58czm802.js?dpl=nogit-1791217996","/_next/static/chunks/3v6lxgtmi9vqz.js?dpl=nogit-1791217996","/_next/static/chunks/13gj59kzq50t_.js?dpl=nogit-1791217996","/_next/static/chunks/3q5gc8lbwr4b4.js?dpl=nogit-1791217996","/_next/static/chunks/0wl6wuakgnlec.js?dpl=nogit-1791217996","/_next/static/chunks/30w6c7jj-mxyi.js?dpl=nogit-1791217996","/_next/static/chunks/2qk8b2y5gyu_0.js?dpl=nogit-1791217996","/_next/static/chunks/3lwy4_ovl68-o.js?dpl=nogit-1791217996","/_next/static/chunks/1hnuhh5t7cfaj.js?dpl=nogit-1791217996","/_next/static/chunks/36nndwkz7iik3.js?dpl=nogit-1791217996","/_next/static/chunks/24srd-xd1m5z8.js?dpl=nogit-1791217996","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1791217996","/_next/static/chunks/1d7tjnrc0fv5y.js?dpl=nogit-1791217996","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1791217996"],"FlashcardAccessBranch"] 37:I[315438,["/_next/static/chunks/34batdc-i3b0_.js?dpl=nogit-1791217996","/_next/static/chunks/2_6olli-sutu3.js?dpl=nogit-1791217996","/_next/static/chunks/0zcakt1-boe_f.js?dpl=nogit-1791217996","/_next/static/chunks/0yuh9obhrf6py.js?dpl=nogit-1791217996","/_next/static/chunks/3mz725-y91ph6.js?dpl=nogit-1791217996","/_next/static/chunks/2x_dbpl3b_l2r.js?dpl=nogit-1791217996","/_next/static/chunks/13_9hjun60hj-.js?dpl=nogit-1791217996","/_next/static/chunks/2bxmml65nu49g.js?dpl=nogit-1791217996","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1791217996","/_next/static/chunks/0d3f1nmeak_z5.js?dpl=nogit-1791217996","/_next/static/chunks/2gjyu-jrwu-fu.js?dpl=nogit-1791217996","/_next/static/chunks/38w1x0vrld4-w.js?dpl=nogit-1791217996","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1791217996","/_next/static/chunks/3kzt2piec6aoa.js?dpl=nogit-1791217996","/_next/static/chunks/19ijf68pshdcn.js?dpl=nogit-1791217996","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1791217996","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1791217996","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1791217996","/_next/static/chunks/10rmxw_yiwj40.js?dpl=nogit-1791217996","/_next/static/chunks/40lyu17d590zu.js?dpl=nogit-1791217996","/_next/static/chunks/2g-t2n9ahs3tn.js?dpl=nogit-1791217996","/_next/static/chunks/1g1suj21ijg7y.js?dpl=nogit-1791217996","/_next/static/chunks/3lz9pr5v38m4h.js?dpl=nogit-1791217996","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1791217996","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1791217996","/_next/static/chunks/2oijhb0tdir9b.js?dpl=nogit-1791217996","/_next/static/chunks/2eanemqjnv2vr.js?dpl=nogit-1791217996","/_next/static/chunks/44nm8-o05iplc.js?dpl=nogit-1791217996","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1791217996","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1791217996","/_next/static/chunks/2r29ujce72_54.js?dpl=nogit-1791217996","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1791217996","/_next/static/chunks/1coblm1-go81_.js?dpl=nogit-1791217996","/_next/static/chunks/0jt4ynafgg-jc.js?dpl=nogit-1791217996","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1791217996","/_next/static/chunks/0qdwqau744_ry.js?dpl=nogit-1791217996","/_next/static/chunks/2eycy5cqzjdqf.js?dpl=nogit-1791217996","/_next/static/chunks/33z1jiacs_jrz.js?dpl=nogit-1791217996","/_next/static/chunks/0w7ow4sfu0tl_.js?dpl=nogit-1791217996","/_next/static/chunks/3it1o0ex-l5qz.js?dpl=nogit-1791217996","/_next/static/chunks/1eyu-5752jh17.js?dpl=nogit-1791217996","/_next/static/chunks/28uw5fp_u1bnm.js?dpl=nogit-1791217996","/_next/static/chunks/3ybwgs28on6c8.js?dpl=nogit-1791217996","/_next/static/chunks/0ixdj_i1afhld.js?dpl=nogit-1791217996","/_next/static/chunks/20_c60cgo1g9g.js?dpl=nogit-1791217996","/_next/static/chunks/075i0tnxt4not.js?dpl=nogit-1791217996","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1791217996","/_next/static/chunks/2ryoj58czm802.js?dpl=nogit-1791217996","/_next/static/chunks/3v6lxgtmi9vqz.js?dpl=nogit-1791217996","/_next/static/chunks/13gj59kzq50t_.js?dpl=nogit-1791217996","/_next/static/chunks/3q5gc8lbwr4b4.js?dpl=nogit-1791217996","/_next/static/chunks/0wl6wuakgnlec.js?dpl=nogit-1791217996","/_next/static/chunks/30w6c7jj-mxyi.js?dpl=nogit-1791217996","/_next/static/chunks/2qk8b2y5gyu_0.js?dpl=nogit-1791217996","/_next/static/chunks/3lwy4_ovl68-o.js?dpl=nogit-1791217996","/_next/static/chunks/1hnuhh5t7cfaj.js?dpl=nogit-1791217996","/_next/static/chunks/36nndwkz7iik3.js?dpl=nogit-1791217996","/_next/static/chunks/24srd-xd1m5z8.js?dpl=nogit-1791217996","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1791217996","/_next/static/chunks/1d7tjnrc0fv5y.js?dpl=nogit-1791217996","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1791217996"],"TopicFlashcardRunner"] 24:[["$","$L33",null,{"feature":"flashcards"}],"$L34",["$","$L35",null,{"href":"/igcse/maths/edexcel/grade-6-6-11-sector-areas-and-arc-lengths/flashcards","label":"Sector Areas and Arc Lengths","subjectCode":"igcse_maths","surface":"flashcards"}],["$","$L36",null,{"runner":["$","div",null,{"className":"min-h-0 flex-1 overflow-hidden bg-background","children":["$","$L37",null,{"decks":[{"id":"1ff34690-9735-4ab9-9477-4ecab97e2bf7","title":"Sector Areas and Arc Lengths Flashcards","topicId":"851df10b-d44a-4533-aa59-01fe4cb69cab","topicSlug":"grade-6-6-11-sector-areas-and-arc-lengths","cards":[{"id":"66e0cdb9-d88e-4519-83e7-3f930b77f2e4","cardType":"basic","points":1,"front":"Which two types of lines enclose a circle sector?","back":"

Two radii
One arc

","mcqOptions":[{"text":"

Two radii
One arc

","correct":true,"explanation":"The two radii run from the centre to the circumference, while the arc joins their endpoints along the circle, together forming the sector’s boundary."},{"text":"

Two chords
One arc

","correct":false,"explanation":"Chords join two points on the circumference and do not necessarily pass through the centre. A sector is enclosed by two radii and one arc."},{"text":"

One radius
One chord

","correct":false,"explanation":"Confusing a sector with another region leads to including a chord. A sector’s straight boundaries are two radii, and its curved boundary is one arc."},{"text":"

Two radii
One chord

","correct":false,"explanation":"The endpoints of the radii are joined around the circumference by an arc, not directly by a chord. The correct boundaries are two radii and one arc."}]},{"id":"e6d8c996-34b3-432a-81d2-530e8ba6af55","cardType":"basic","points":1,"front":"Formula for the circumference of a full circle.","back":"$$C = 2\\pi r$","mcqOptions":[{"text":"$$C = 2\\pi r$","correct":true,"explanation":"Circumference is the distance around the circle. Since the diameter is $2r$ and circumference equals $\\pi$ times the diameter, $C=2\\pi r$."},{"text":"$$C = \\pi r$","correct":false,"explanation":"This treats the radius as though it were the diameter, making the circumference half its correct value. Using the diameter $2r$ gives $C=2\\pi r$."},{"text":"$$C = 2\\pi r^2$","correct":false,"explanation":"Squaring the radius is associated with area, not circumference, and gives square units. Circumference is a length, so the correct formula is $C=2\\pi r$."},{"text":"$$C = \\pi r^2$","correct":false,"explanation":"This is the formula for the area of a circle, not its circumference. The distance around a circle is calculated using $C=2\\pi r$."}]},{"id":"d9fd204f-e9da-40e4-8c8b-7d45b2ef0754","cardType":"basic","points":1,"front":"Formula for the area of a full circle.","back":"$$A = \\pi r^2$","mcqOptions":[{"text":"$$A = \\pi r^2$","correct":true,"explanation":"A circle’s area depends on the square of its radius, so the formula is $A=\\pi r^2$. The squared radius also produces the required square units."},{"text":"$$A = 2\\pi r$","correct":false,"explanation":"This calculates the circumference, which is the distance around the circle rather than its area. The area enclosed by the circle is $A=\\pi r^2$."},{"text":"$$A = \\pi r$","correct":false,"explanation":"Failing to square the radius gives linear rather than square units. Because area measures a two-dimensional region, the correct formula is $A=\\pi r^2$."},{"text":"$$A = 2\\pi r^2$","correct":false,"explanation":"The unnecessary factor of $2$ doubles the circle’s area. The full area is found by multiplying the squared radius by $\\pi$, giving $A=\\pi r^2$."}]},{"id":"2954cc66-6d91-4c7b-8b45-53bb065261c7","cardType":"cloze","points":null,"front":"A sector with central angle $\\theta$ represents the fraction $\\text{[...]}$ of a whole circle.","back":"A sector with central angle $\\theta$ represents the fraction $\\boxed{\\frac{\\theta}{360}}$ of a whole circle.","mcqOptions":[{"text":"$$\\frac{\\theta}{360}$","correct":true,"explanation":"A full turn contains $360$ degrees, so a central angle of $\\theta$ degrees forms $\\theta$ out of $360$ equal angular parts of the circle."},{"text":"$$\\frac{360}{\\theta}$","correct":false,"explanation":"Reversing the fraction gives how many such angles fit into $360$ degrees, not the fraction occupied by one sector. The required fraction is $\\frac{\\theta}{360}$."},{"text":"$$\\frac{\\theta}{180}$","correct":false,"explanation":"Dividing by $180$ compares the angle with a semicircle rather than a whole circle. A whole turn is $360$ degrees, so the fraction is $\\frac{\\theta}{360}$."},{"text":"$$\\frac{2\\theta}{360}$","correct":false,"explanation":"Doubling the central angle makes the fraction twice as large as the sector actually occupies. The angle should be compared directly with $360$, giving $\\frac{\\theta}{360}$."}]},{"id":"135e9763-ab40-40e6-a73d-1efe5213496a","cardType":"basic","points":1,"front":"Formula for the area of a sector.","back":"$$A = \\frac{\\theta}{360} \\times \\pi r^2$","mcqOptions":[{"text":"$$A = \\frac{\\theta}{360} \\times \\pi r^2$","correct":true,"explanation":"The sector occupies the fraction $\\frac{\\theta}{360}$ of the full circle. Multiplying this fraction by the circle’s area $\\pi r^2$ gives the sector’s area."},{"text":"$$A = \\frac{360}{\\theta} \\times \\pi r^2$","correct":false,"explanation":"The angular fraction has been inverted, producing an area larger than the whole circle for most sectors. The correct fraction is $\\frac{\\theta}{360}$, so $A=\\frac{\\theta}{360}\\times\\pi r^2$."},{"text":"$$A = \\frac{\\theta}{360} \\times 2\\pi r$","correct":false,"explanation":"This multiplies the sector fraction by the circle’s circumference, so it calculates arc length rather than area. Sector area uses $\\pi r^2$, giving $A=\\frac{\\theta}{360}\\times\\pi r^2$."},{"text":"$$A = \\frac{\\theta}{180} \\times \\pi r^2$","correct":false,"explanation":"Using $180$ compares the central angle with a semicircle and doubles the required area. A whole circle has $360$ degrees, so use $A=\\frac{\\theta}{360}\\times\\pi r^2$."}]},{"id":"28fbd245-43de-453e-8c33-f97544fb41fc","cardType":"basic","points":1,"front":"What does arc length represent in a sector?","back":"The length of the curved edge.","mcqOptions":[{"text":"The length of the curved edge.","correct":true,"explanation":"The arc is the part of the circle’s circumference between the endpoints of the two radii, so arc length measures the sector’s curved boundary."},{"text":"The length of the two radii.","correct":false,"explanation":"The radii form the sector’s straight edges, not its arc. Arc length measures only the curved section of the circumference between the two radii."},{"text":"The area of the curved region.","correct":false,"explanation":"Arc length is a one-dimensional measurement, whereas the region enclosed by the radii and arc is the sector’s area. It measures the curved edge only."},{"text":"The length of the straight chord.","correct":false,"explanation":"A chord joins two points on the circumference by a straight line, while an arc follows the circumference. Arc length is the length of the curved edge."}]},{"id":"2ed35f6a-f534-4a12-88ec-1e2c86473ca9","cardType":"basic","points":1,"front":"Formula for the arc length ($L$) of a sector.","back":"$$L = \\frac{\\theta}{360} \\times 2\\pi r$","mcqOptions":[{"text":"$$L = \\frac{\\theta}{360} \\times 2\\pi r$","correct":true,"explanation":"The arc occupies the fraction $\\frac{\\theta}{360}$ of the full circumference. Multiplying that fraction by $2\\pi r$ therefore gives the required arc length."},{"text":"$$L = \\frac{360}{\\theta} \\times 2\\pi r$","correct":false,"explanation":"Inverting the angular fraction usually makes the result larger than the full circumference. The arc is $\\frac{\\theta}{360}$ of the circumference, so $L=\\frac{\\theta}{360}\\times2\\pi r$."},{"text":"$$L = \\frac{\\theta}{360} \\times \\pi r^2$","correct":false,"explanation":"Multiplying by $\\pi r^2$ calculates sector area and produces square units. Arc length requires the full circumference $2\\pi r$, giving $L=\\frac{\\theta}{360}\\times2\\pi r$."},{"text":"$$L = \\frac{\\theta}{180} \\times 2\\pi r$","correct":false,"explanation":"Using $180$ treats a semicircle as the full turn and doubles the arc length. The central angle must be divided by $360$, giving $L=\\frac{\\theta}{360}\\times2\\pi r$."}]},{"id":"64563df9-0872-4087-a5fd-4ec288b8e5e7","cardType":"basic","points":1,"front":"What defines a major sector?","back":"A sector where the central angle is greater than 180 degrees.","mcqOptions":[{"text":"A sector where the central angle is greater than 180 degrees.","correct":true,"explanation":"A central angle greater than $180$ degrees covers more than half of the circle, so the resulting region is classified as a major sector."},{"text":"A sector where the central angle is less than 180 degrees.","correct":false,"explanation":"An angle below $180$ degrees forms less than half a circle, which defines a minor sector. A major sector has a central angle greater than $180$ degrees."},{"text":"A sector where the central angle is equal to 180 degrees.","correct":false,"explanation":"An angle of exactly $180$ degrees forms a semicircle, not a major sector. A major sector must have a central angle strictly greater than $180$ degrees."},{"text":"A sector where the central angle is greater than 360 degrees.","correct":false,"explanation":"A standard sector’s central angle cannot exceed one complete turn of $360$ degrees. A major sector is defined by an angle greater than $180$ but below $360$ degrees."}]},{"id":"9bc9a9fe-280c-4d09-946f-1a8b8b18ad6e","cardType":"basic","points":2,"front":"Which three lengths must be added to find the perimeter of a sector?","back":"

The arc length
Two radii

","mcqOptions":[{"text":"

The arc length
Two radii

","correct":true,"explanation":"The curved arc and the two radii form the sector’s complete boundary, so adding these three lengths gives its perimeter."},{"text":"

The arc length
Two diameters

","correct":false,"explanation":"Using diameters doubles the two straight boundary lengths. A sector is bounded by its arc length and two radii, not two diameters."},{"text":"

The chord length
Two radii

","correct":false,"explanation":"The chord joins the arc’s endpoints but is not part of the sector’s boundary. The perimeter consists of the arc length and two radii."},{"text":"

The arc length
One radius

","correct":false,"explanation":"This omits one of the sector’s straight sides. Both radii belong to the boundary, so the arc length and two radii must be added."}]},{"id":"90b2620a-36a9-4e5b-8eb3-634e0029f4c6","cardType":"basic","points":1,"front":"Formula for the perimeter ($P$) of a sector using arc length $L$ and radius $r$.","back":"$$P = L + 2r$","mcqOptions":[{"text":"$$P = L + 2r$","correct":true,"explanation":"A sector’s boundary contains the curved arc of length $L$ and two straight radii of length $r$, giving $P=L+r+r=L+2r$."},{"text":"$$P = L + r$","correct":false,"explanation":"This includes only one radius and therefore misses one straight side of the sector. The correct perimeter is $P=L+2r$."},{"text":"$$P = 2L + 2r$","correct":false,"explanation":"This incorrectly counts the curved arc twice. A sector has one arc and two radii, so its perimeter is $P=L+2r$."},{"text":"$$P = L + 2\\pi r$","correct":false,"explanation":"The term $2\\pi r$ is the circumference of a complete circle, not the sector’s two straight sides. The correct formula is $P=L+2r$."}]},{"id":"41ba6bc9-e91a-454e-b18d-20bd75d6b118","cardType":"cloze","points":null,"front":"A semicircle has an area equal to $\\text{[...]}$.","back":"A semicircle has an area equal to $\\boxed{\\frac{1}{2}\\pi r^2}$.","mcqOptions":[{"text":"$$\\frac{1}{2}\\pi r^2$","correct":true,"explanation":"A semicircle is half of a complete circle. Since a circle has area $\\pi r^2$, halving it gives $\\frac{1}{2}\\pi r^2$."},{"text":"$$\\pi r^2$","correct":false,"explanation":"This is the area of a complete circle and does not account for the shape being halved. A semicircle has area $\\frac{1}{2}\\pi r^2$."},{"text":"$$\\frac{1}{2}\\pi r$","correct":false,"explanation":"Omitting the square on the radius produces units of length rather than area. The semicircle’s area is $\\frac{1}{2}\\pi r^2$."},{"text":"$$\\frac{1}{4}\\pi r^2$","correct":false,"explanation":"This finds the area of a quarter-circle rather than a semicircle. A semicircle is half a circle, so its area is $\\frac{1}{2}\\pi r^2$."}]},{"id":"2f372bb8-fefd-46e4-bfbd-9659b70fc5f3","cardType":"basic","points":2,"front":"Outline the general strategy for finding a shaded region involving two shapes.","back":"

Calculate the area of the larger shape
Calculate the area of the smaller shape
Subtract the smaller area from the larger

","mcqOptions":[{"text":"

Calculate the area of the larger shape
Calculate the area of the smaller shape
Subtract the smaller area from the larger

","correct":true,"explanation":"The shaded region is the part of the larger shape remaining after the smaller shape is removed, so its area is larger area minus smaller area."},{"text":"

Calculate the area of the larger shape
Calculate the area of the smaller shape
Add the smaller area to the larger

","correct":false,"explanation":"Adding counts both complete shapes instead of removing the unshaded inner part. The shaded area is found by subtracting the smaller area from the larger."},{"text":"

Calculate the area of the smaller shape
Calculate the area of the larger shape
Subtract the larger area from the smaller

","correct":false,"explanation":"Reversing the subtraction usually produces a negative result, which cannot represent an area. Subtract the smaller area from the larger area instead."},{"text":"

Calculate the perimeter of the larger shape
Calculate the perimeter of the smaller shape
Subtract the smaller perimeter from the larger

","correct":false,"explanation":"Perimeters measure boundary lengths and cannot determine the size of a shaded region. Calculate both areas, then subtract the smaller area from the larger."}]},{"id":"d6d35d71-b5bc-4f52-80b8-dcc3a8021354","cardType":"basic","points":1,"front":"Shortcut formula for sector area if the arc length ($L$) and radius ($r$) are known.","back":"$$A = \\frac{1}{2}rL$","mcqOptions":[{"text":"$$A = \\frac{1}{2}rL$","correct":true,"explanation":"Using $L=r\\theta$ with the sector formula $A=\\frac{1}{2}r^2\\theta$ gives $A=\\frac{1}{2}rL$ when the arc length and radius are known."},{"text":"$$A = rL$","correct":false,"explanation":"This misses the factor of one half and therefore gives twice the sector’s actual area. The correct shortcut is $A=\\frac{1}{2}rL$."},{"text":"$$A = \\frac{1}{2}r^2L$","correct":false,"explanation":"The extra factor of $r$ gives cubic units, so the result cannot be an area. The dimensionally correct formula is $A=\\frac{1}{2}rL$."},{"text":"$$A = \\frac{L}{2r}$","correct":false,"explanation":"Dividing arc length by radius relates to the angle in radians and produces no area units. Sector area is given by $A=\\frac{1}{2}rL$."}]},{"id":"c33eec3a-6cde-4684-89a3-2be0a6c4caa8","cardType":"cloze","points":null,"front":"If a question asks for a value \"in terms of $\\pi$\", you must leave the $\\text{[...]}$ symbol in your final answer.","back":"If a question asks for a value \"in terms of $\\pi$\", you must leave the $\\boxed{\\pi}$ symbol in your final answer.","mcqOptions":[{"text":"$$\\pi$","correct":true,"explanation":"An answer in terms of $\\pi$ must retain the exact symbol rather than replacing it with a decimal approximation, such as $3.142$."},{"text":"$$r$","correct":false,"explanation":"The radius may remain as a variable only when it is unknown, but “in terms of $\\pi$” specifically requires the $\\pi$ symbol to remain."},{"text":"$$A$","correct":false,"explanation":"The symbol $A$ usually labels area and is not what the instruction refers to. An answer in terms of $\\pi$ must leave $\\pi$ uncalculated."},{"text":"$$\\theta$","correct":false,"explanation":"The symbol $\\theta$ represents an angle, not the circle constant named in the instruction. The final answer must retain the $\\pi$ symbol."}]},{"id":"3ec1954a-f718-43ff-95ea-5bbdfc4ee008","cardType":"cloze","points":null,"front":"If a semicircle is described as having a diameter of 10 cm, the value of $r$ used in formulas is $\\text{[...]}$ cm.","back":"If a semicircle is described as having a diameter of 10 cm, the value of $r$ used in formulas is $\\boxed{5}$ cm.","mcqOptions":[{"text":"$$5$","correct":true,"explanation":"The radius is half the diameter, so a diameter of $10$ cm gives $r=10\\div2=5$ cm."},{"text":"$$10$","correct":false,"explanation":"This treats the given diameter as though it were the radius. Since the radius is half the diameter, the correct value is $5$ cm."},{"text":"$$20$","correct":false,"explanation":"This doubles the diameter instead of halving it. The radius is the distance from the centre to the circumference, so it is $5$ cm."},{"text":"$$100$","correct":false,"explanation":"This squares the diameter, confusing a length with a step used in area calculations. The formula requires the radius, which is $10\\div2=5$ cm."}]},{"id":"fe4e187a-6810-4bca-971b-9e000d369bf0","cardType":"basic","points":2,"front":"Why should you keep the full calculator value for calculations and only round at the final answer?","back":"To prevent rounding errors that could make the final 3 significant figure answer inaccurate.","mcqOptions":[{"text":"To prevent rounding errors that could make the final 3 significant figure answer inaccurate.","correct":true,"explanation":"Keeping full calculator precision prevents small intermediate rounding differences from accumulating. Rounding only the final result gives the most accurate answer to 3 significant figures."},{"text":"To ensure every intermediate value is rounded to 3 significant figures before it is reused.","correct":false,"explanation":"Rounding each intermediate value can accumulate errors and alter the final result. Keep full calculator values throughout and round only the final answer to 3 significant figures."},{"text":"To avoid converting between degrees and radians until the final line of working.","correct":false,"explanation":"Angle-unit conversion is separate from the issue of premature rounding. Full calculator values are retained to prevent accumulated rounding errors before the final answer."},{"text":"To ensure the final answer is always rounded up rather than to the nearest value.","correct":false,"explanation":"Significant-figure rounding may require rounding either up or down, depending on the next digit. Full values are kept to make that final rounding accurate."}]},{"id":"aa059235-a743-4120-8955-eaf0d190437c","cardType":"basic","points":2,"front":"How do you calculate the percentage of a rectangle that is shaded?","back":"$$\\frac{\\text{shaded area}}{\\text{rectangle area}} \\times 100$","mcqOptions":[{"text":"$$\\frac{\\text{shaded area}}{\\text{rectangle area}} \\times 100$","correct":true,"explanation":"Dividing the shaded area by the rectangle’s total area gives the shaded proportion. Multiplying this decimal by 100 converts the proportion into a percentage."},{"text":"$$\\frac{\\text{rectangle area}}{\\text{shaded area}} \\times 100$","correct":false,"explanation":"This reverses the required fraction and can produce a percentage greater than 100%. The shaded area must be divided by the total rectangle area, then multiplied by 100."},{"text":"$$\\frac{\\text{shaded area}}{\\text{rectangle area}}$","correct":false,"explanation":"This calculates the shaded proportion as a decimal or fraction but does not convert it to a percentage. The result must also be multiplied by 100."},{"text":"$$\\frac{\\text{unshaded area}}{\\text{rectangle area}} \\times 100$","correct":false,"explanation":"This calculates the percentage that is unshaded rather than shaded. The numerator must be the shaded area, while the denominator remains the total rectangle area."}]},{"id":"087d10ac-f5f4-4444-9a7d-ff7f12a82a07","cardType":"cloze","points":null,"front":"A common mistake when calculating sector perimeter is to calculate only the arc length and forget to add the $\\text{[...]}$.","back":"A common mistake when calculating sector perimeter is to calculate only the arc length and forget to add the $\\boxed{two radii}$.","mcqOptions":[{"text":"$$two radii$","correct":true,"explanation":"A sector’s boundary consists of the curved arc and two straight radii. Its perimeter is therefore the arc length plus the lengths of both radii."},{"text":"$$radius$","correct":false,"explanation":"Adding only one radius misses one straight side of the sector. The complete perimeter includes the arc length and two radii, one on each side."},{"text":"$$diameter$","correct":false,"explanation":"A sector does not generally have a diameter as part of its boundary. Its two straight boundary edges are radii, so both radii must be added."},{"text":"$$chord$","correct":false,"explanation":"A chord joins the arc’s endpoints directly and belongs to a segment boundary, not a sector boundary. A sector’s perimeter includes the arc and two radii."}]},{"id":"19d1e0a4-0707-4398-9e34-42f611cd212c","cardType":"cloze","points":null,"front":"A $200^\\circ$ sector is more than half of a circle because it is larger than $\\text{[...]}$.","back":"A $200^\\circ$ sector is more than half of a circle because it is larger than $\\boxed{180^\\circ}$.","mcqOptions":[{"text":"$$180^\\circ$","correct":true,"explanation":"Half a full turn of $360^\\circ$ is $180^\\circ$. Since $200^\\circ$ is greater than $180^\\circ$, the sector occupies more than half the circle."},{"text":"$$90^\\circ$","correct":false,"explanation":"An angle of $90^\\circ$ represents one quarter of a circle, not one half. The correct comparison angle for half a circle is $180^\\circ$."},{"text":"$$200^\\circ$","correct":false,"explanation":"This repeats the sector’s own angle rather than giving the half-circle benchmark. Half of $360^\\circ$ is $180^\\circ$, which $200^\\circ$ exceeds."},{"text":"$$360^\\circ$","correct":false,"explanation":"An angle of $360^\\circ$ represents the whole circle, so $200^\\circ$ is not larger than it. The angle representing half a circle is $180^\\circ$."}]},{"id":"4637a33b-3417-486d-ad84-9f5649d2408c","cardType":"basic","points":2,"front":"Find the area of a sector with radius 8 cm and arc length $5\\pi$ cm.","back":"$$20\\pi$ cm$^2$","mcqOptions":[{"text":"$$20\\pi$ cm$^2$","correct":true,"explanation":"Using sector area $A=\\frac{1}{2}rs$ with radius $8$ cm and arc length $5\\pi$ cm gives $A=\\frac{1}{2}\\times8\\times5\\pi=20\\pi$ cm$^2$."},{"text":"$$40\\pi$ cm$^2$","correct":false,"explanation":"This uses $A=rs$ and omits the factor of $\\frac{1}{2}$. Sector area is $\\frac{1}{2}rs$, giving $\\frac{1}{2}\\times8\\times5\\pi=20\\pi$ cm$^2$."},{"text":"$$10\\pi$ cm$^2$","correct":false,"explanation":"This introduces an extra division by 2, effectively using $A=\\frac{1}{4}rs$. The correct formula is $A=\\frac{1}{2}rs$, which gives $20\\pi$ cm$^2$."},{"text":"$$64\\pi$ cm$^2$","correct":false,"explanation":"This is the area $\\pi r^2$ of the entire circle and ignores the given arc length. Using $A=\\frac{1}{2}rs$ gives the sector area $20\\pi$ cm$^2$."}]}]}],"examCountdown":{"examDate":"2027-05-14","paperLabel":"Paper 1"},"heading":"Sector Areas and Arc Lengths","title":"Sector Areas and Arc Lengths Flashcards","topbar":{"backHref":"/igcse/maths/edexcel/flashcards"},"topicSidebar":"$L38"}]}],"topicId":"851df10b-d44a-4533-aa59-01fe4cb69cab","walled":"$L39"}],"$L3a","$L3b"]