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Solving Quadratics IGCSE Maths exam-style questions with worked solutions on MathsGenie.\",\"learningResourceType\":\"Practice questions\",\"educationalLevel\":\"IGCSE\",\"about\":{\"@type\":\"Thing\",\"name\":\"Solving Quadratics\"},\"url\":\"https://mathsgenie.co.uk/igcse/maths/edexcel/grade-5-5-6-solving-quadratics/questions/q13\",\"inLanguage\":\"en-GB\",\"provider\":{\"@id\":\"https://mathsgenie.co.uk/#organization\"}}"}}],["$","div",null,{"className":"min-h-0 w-full flex-1 overflow-hidden bg-background","children":["$","$L39",null,{"backHref":"/igcse/maths/edexcel/questions","basePath":"/igcse/maths/edexcel/grade-5-5-6-solving-quadratics/questions","formulaUrl":null,"initialIndex":12,"initialQuestionWindow":[{"id":"5f32ba50-332a-42a7-996d-1965f7e48ce8","revisionId":"96d6c54c-c782-463a-b41f-a512d06cde92","questionNumber":"12","questionType":"LA","specification":"","difficulty":2,"difficultyBand":"medium","totalMarks":3,"sourceTitle":"Solving Quadratics","calculatorUse":null,"isCalculation":true,"parts":[{"id":"37eb367c-0702-4203-b173-7fa45d70ee47","label":"0","content":"Solve $x^2 + 11x - 42 = 0$","markscheme":"- Factorises the quadratic: $(x - 3)(x + 14) = 0$ M2\n- Correct solutions: $x = 3$ or $x = -14$ A1","marks":3,"order":0,"markingRubric":{"totalMarks":3,"points":[{"id":"p1","marks":1,"description":"Identifies factors of -42 that sum to 11 (-3 and 14).","code":"M"},{"id":"p2","marks":1,"description":"Writes the quadratic in factorised form $(x-3)(x+14) = 0$.","code":"M"},{"id":"p3","marks":1,"description":"Final answers $x = 3$ and $x = -14$.","code":"A"}],"finalAnswers":["x = 3, x = -14"],"generatedAt":"2026-05-07T01:58:33.588Z","modelVersion":"gemini-3-flash-preview"},"tableImages":[],"explanation":{"methods":[{"id":"factorising","label":"Factorising","steps":[{"type":"text","order":0,"title":"Find the pair","content":"We need two numbers whose **product** is $-42$ and whose **sum** is $11$. They are $-3$ and $14$: $(-3)(14)=-42$ and $-3+14=11$.","highlights":[{"text":"Solve $x^2 + 11x - 42 = 0$","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"\\htmlData{anchor=original}{x^2+11x-42=0}"},{"latex":"\\htmlData{anchor=factorised}{(x-3)(x+14)=0}"}],"connections":[{"to":"factorised","from":"original","color":"sky","label":"factorise","style":"solid"}]},"order":1,"title":"Write the factors","description":"Use those two numbers as the constants in two brackets. Reaching the correct factorisation earns the M2 marks."},{"type":"text","order":2,"title":"Apply zero-product rule","content":"If two factors multiply to give $0$, at least one factor must be $0$. Therefore set each bracket equal to $0$."},{"type":"hyper_latex","block":{"nodes":[{"latex":"\\htmlData{anchor=first_start}{\\color{@green}{x-3=0}}"},{"latex":"\\htmlData{anchor=first_end}{\\color{@green}{x=3}}"},{"latex":"\\htmlData{anchor=second_start}{\\color{@orange}{x+14=0}}"},{"latex":"\\htmlData{anchor=second_end}{\\color{@orange}{x=-14}}"}],"highlights":[{"color":"green","style":"text-color-with-background","anchor":"first_end"},{"color":"orange","style":"text-color-with-background","anchor":"second_end"}],"connections":[{"to":"first_end","from":"first_start","color":"green","label":"add 3","style":"solid"},{"to":"second_end","from":"second_start","color":"orange","label":"subtract 14","style":"solid"}]},"order":3,"title":"Solve each bracket","description":"Solve the two one-step equations separately. Giving both roots correctly earns the A1 mark."}]}],"generatedAt":"2026-07-21T04:13:28.586Z","modelVersion":"gpt-5.6-terra","explanationVersion":"v3"},"options":[]}],"options":[],"explanation":null,"firstAttemptFullMarks":null,"walkthroughVideo":null},{"id":"30878799-3a3a-4c2d-984d-545b84d7778b","revisionId":"e305cd60-9e36-474d-b678-2b4b8067fa97","questionNumber":"13","questionType":"LA","specification":"","difficulty":2,"difficultyBand":"medium","totalMarks":3,"sourceTitle":"Solving Quadratics","calculatorUse":null,"isCalculation":true,"parts":[{"id":"54fde6fc-3fa3-45c8-8597-c0c1f8f30ead","label":"0","content":"Solve $a^2 - 10a + 16 = 0$","markscheme":"- Factorises the quadratic: $(a - 2)(a - 8) = 0$ M2\n- Correct solutions: $a = 2$ or $a = 8$ A1","marks":3,"order":0,"markingRubric":{"totalMarks":3,"points":[{"id":"p1","marks":1,"description":"Identifies factors of 16 that sum to -10 (-2 and -8).","code":"M"},{"id":"p2","marks":1,"description":"Writes the quadratic in factorised form $(a-2)(a-8) = 0$.","code":"M"},{"id":"p3","marks":1,"description":"Final answers $a = 2$ and $a = 8$.","code":"A"}],"finalAnswers":["a = 2, a = 8"],"generatedAt":"2026-05-07T01:58:33.588Z","modelVersion":"gemini-3-flash-preview"},"tableImages":[],"explanation":{"methods":[{"id":"factorising","label":"Factorising","steps":[{"type":"hyper_latex","block":{"nodes":[{"latex":"\\htmlData{anchor=original}{a^2-10a+16=0}"},{"latex":"\\htmlData{anchor=factorised}{(a-2)(a-8)=0}"}],"connections":[{"to":"factorised","from":"original","color":"sky","label":"factorise","style":"solid"}]},"order":1,"title":"Factorise the quadratic","description":"The pair $2$ and $8$ multiplies to $16$ and adds to $10$, so use negative signs in both brackets. This factorisation earns the M2 mark."},{"type":"text","order":2,"title":"Use the zero product","content":"If two factors multiply to give $0$, at least one factor must equal $0$. So solve each bracket separately.","highlights":[{"text":"Solve $a^2 - 10a + 16 = 0$","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"\\htmlData{anchor=firstfactor}{a-2=0}"},{"latex":"\\htmlData{anchor=firstroot}{a=2}"},{"latex":"\\htmlData{anchor=secondfactor}{a-8=0}"},{"latex":"\\htmlData{anchor=secondroot}{a=8}"}],"highlights":[{"color":"green","style":"text-color-with-background","anchor":"firstroot"},{"color":"orange","style":"text-color-with-background","anchor":"secondroot"}],"connections":[{"to":"firstroot","from":"firstfactor","color":"green","label":"add 2"},{"to":"secondroot","from":"secondfactor","color":"orange","label":"add 8"}]},"order":3,"title":"Solve each factor","description":"Set each factor equal to zero. The two resulting values are the solutions, earning the A1 mark."}]}],"generatedAt":"2026-07-21T03:17:42.668Z","modelVersion":"gpt-5.6-terra","explanationVersion":"v3"},"options":[]}],"options":[],"explanation":null,"firstAttemptFullMarks":null,"walkthroughVideo":null},{"id":"d600099b-0ecf-46f9-a730-89d28e2f26b4","revisionId":"7d59d5ef-86b5-423d-b0f4-5053ef15fb5a","questionNumber":"15","questionType":"LA","specification":"","difficulty":2,"difficultyBand":"medium","totalMarks":3,"sourceTitle":"Solving Quadratics","calculatorUse":null,"isCalculation":true,"parts":[{"id":"2d1b9a0a-3c0e-461a-a690-605ed72d557e","label":"0","content":"Solve $x^2 + 3x - 54 = 0$","markscheme":"- Factorises the quadratic: $(x + 9)(x - 6) = 0$ M2\n- Correct solutions: $x = -9$ or $x = 6$ A1","marks":3,"order":0,"markingRubric":{"totalMarks":3,"points":[{"id":"p1","marks":1,"description":"Identifies factors of -54 that sum to 3 (9 and -6).","code":"M"},{"id":"p2","marks":1,"description":"Writes the quadratic in factorised form $(x+9)(x-6) = 0$.","code":"M"},{"id":"p3","marks":1,"description":"Final answers $x = -9$ and $x = 6$.","code":"A"}],"finalAnswers":["x = -9, x = 6"],"generatedAt":"2026-05-07T01:58:33.588Z","modelVersion":"gemini-3-flash-preview"},"tableImages":[],"explanation":{"methods":[{"id":"factorising","label":"Factorising","steps":[{"type":"text","order":0,"title":"Find two numbers","content":"Find two numbers that multiply to $-54$ and add to $3$. They are $9$ and $-6$:\n\n$$9\\times(-6)=-54,\\qquad 9+(-6)=3.$$","highlights":[{"text":"Solve $x^2 + 3x - 54 = 0$","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$x^2+3x-54=0$"},{"latex":"$$(x+9)(x-6)=0$"}]},"order":1,"title":"Factorise the quadratic","description":"Use the two numbers in the brackets. This factorisation earns the two method marks."},{"type":"text","order":2,"title":"Set each factor zero","content":"If two factors multiply to $0$, at least one factor must equal $0$. So solve each bracket separately:\n\n$$x+9=0\\quad\\text{or}\\quad x-6=0.$$"},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$\\htmlData{anchor=first_factor}{x+9}=0$"},{"latex":"$$\\htmlData{anchor=first_solution}{x=-9}$"},{"latex":"$$\\htmlData{anchor=second_factor}{x-6}=0$"},{"latex":"$$\\htmlData{anchor=second_solution}{x=6}$"}],"highlights":[{"color":"green","style":"text-color-with-background","anchor":"first_solution"},{"color":"green","style":"text-color-with-background","anchor":"second_solution"}],"connections":[{"to":"first_solution","from":"first_factor","color":"green","label":"subtract 9"},{"to":"second_solution","from":"second_factor","color":"green","label":"add 6"}]},"order":3,"title":"Solve both equations","description":"Rearrange each one-step equation to find the two possible values of x. Obtaining both solutions, x = -9 and x = 6, earns the final accuracy mark (A1)."}]}],"generatedAt":"2026-07-21T04:11:26.530Z","modelVersion":"gpt-5.6-terra","explanationVersion":"v3"},"options":[]}],"options":[],"explanation":null,"firstAttemptFullMarks":null,"walkthroughVideo":null}],"subjectCode":"igcse_maths","summaries":[{"id":"8c4a3814-07f4-423e-961b-9108b4e4f481","difficultyBand":"easy","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"2fe541d6-a67a-44eb-9ce4-d6b00ec581ec","difficultyBand":"easy","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"6aeabf1c-53f7-46c3-8e3a-21c54867b5a5","difficultyBand":"easy","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"d076615f-be28-4fd1-b260-315b540ba51b","difficultyBand":"easy","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"aa9ac8b7-21c2-49c0-96bf-6a92f17abe01","difficultyBand":"easy","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"d296e581-2509-4b68-8c33-935b5c6c36ac","difficultyBand":"easy","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"1c0b7c87-d951-4125-819e-b7cb826593be","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"c71b8017-c256-4d93-ad27-580a5b58d5b9","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"7face5c3-4ccc-4d2e-ae9f-d3e8e9df86ce","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"b2cf389a-05e6-4dcf-ad80-4867651ec01c","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"2ada5dd1-ffd8-4c4a-a7cc-c334dd668bd1","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"5f32ba50-332a-42a7-996d-1965f7e48ce8","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"30878799-3a3a-4c2d-984d-545b84d7778b","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"b3935209-66d6-4aa0-8493-f378abbca4d6","difficultyBand":"easy","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"d600099b-0ecf-46f9-a730-89d28e2f26b4","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"df27fdcc-0236-4e33-b25f-ed879ca090fa","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"62eb9144-cf1d-4dde-9d57-dfc5f0eacd47","difficultyBand":"easy","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"7ffc1c73-47e1-4b79-a48f-69185e7cde87","difficultyBand":"medium","calculatorUse":null,"totalMarks":3,"questionType":"LA","isCalculation":true}],"title":"Solving Quadratics","topicId":"05ab8093-6ea6-479e-9714-8bbbf2d95eb6","topicSidebar":"$L3a","topicSlug":"grade-5-5-6-solving-quadratics","topicTitle":"Solving Quadratics"}]}],"$L3b","$L3c"]}]

Solving Quadratics

Question 7

Solving Quadratics Questions

Solving Quadratics

Question 7

Solving Quadratics Questions