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Solving Quadratics IGCSE Maths exam-style questions with worked solutions on MathsGenie.\",\"learningResourceType\":\"Practice questions\",\"educationalLevel\":\"IGCSE\",\"about\":{\"@type\":\"Thing\",\"name\":\"Solving Quadratics\"},\"url\":\"https://mathsgenie.co.uk/igcse/maths/edexcel/grade-5-5-6-solving-quadratics/questions/q10\",\"inLanguage\":\"en-GB\",\"provider\":{\"@id\":\"https://mathsgenie.co.uk/#organization\"}}"}}],["$","div",null,{"className":"min-h-0 w-full flex-1 overflow-hidden bg-background","children":["$","$L39",null,{"backHref":"/igcse/maths/edexcel/questions","basePath":"/igcse/maths/edexcel/grade-5-5-6-solving-quadratics/questions","formulaUrl":null,"initialIndex":9,"initialQuestionWindow":[{"id":"7face5c3-4ccc-4d2e-ae9f-d3e8e9df86ce","revisionId":"33adc4a4-9770-40e4-8dd9-24bcf20f8bde","questionNumber":"9","questionType":"LA","specification":"","difficulty":2,"difficultyBand":"medium","totalMarks":3,"sourceTitle":"Solving Quadratics","calculatorUse":null,"isCalculation":true,"parts":[{"id":"331fd46a-ca72-4c7c-9c06-b1dd3d2478ef","label":"0","content":"Solve $x^2 + 5x + 6 = 0$","markscheme":"- Factorises the quadratic: $(x + 2)(x + 3) = 0$ M2\n- Correct solutions: $x = -2$ or $x = -3$ A1","marks":3,"order":0,"markingRubric":{"totalMarks":3,"points":[{"id":"p1","marks":1,"description":"Identifies factors of 6 that sum to 5 (2 and 3).","code":"M"},{"id":"p2","marks":1,"description":"Writes the quadratic in factorised form $(x+2)(x+3) = 0$.","code":"M"},{"id":"p3","marks":1,"description":"Final answers $x = -2$ and $x = -3$.","code":"A"}],"finalAnswers":["x = -2, x = -3"],"generatedAt":"2026-05-07T01:58:33.588Z","modelVersion":"gemini-3-flash-preview"},"tableImages":[],"explanation":{"methods":[{"id":"factorising","label":"Factorising","steps":[{"type":"text","order":0,"title":"Choose the factor pair","content":"Find two numbers that multiply to give $6$ and add to give $5$. They are $2$ and $3$.\n\nThese numbers become the constants in the two brackets.","highlights":[{"text":"Solve $x^2 + 5x + 6 = 0$","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"\\htmlData{anchor=original}{x^2+5x+6=0}"},{"latex":"\\htmlData{anchor=factorised}{(x+2)(x+3)=0}"}],"connections":[{"to":"factorised","from":"original","color":"sky","label":"factor pair: 2 + 3 = 5, 2 × 3 = 6","style":"solid"}]},"order":1,"title":"Factorise the quadratic","description":"Use 2 and 3 because 2 + 3 = 5 and 2 × 3 = 6. M2: correct factorisation."},{"type":"text","order":2,"title":"Apply zero-product rule","content":"If two factors multiply to make $0$, at least one factor must equal $0$. So solve $x+2=0$ and $x+3=0$ separately."},{"type":"hyper_latex","block":{"nodes":[{"latex":"\\htmlData{anchor=two_from}{x+2=0}"},{"latex":"\\htmlData{anchor=two_to}{x=-2}"},{"latex":"\\htmlData{anchor=three_from}{x+3=0}"},{"latex":"\\htmlData{anchor=three_to}{x=-3}"}],"highlights":[{"color":"orange","style":"text-color-with-background","anchor":"two_to"},{"color":"green","style":"text-color-with-background","anchor":"three_to"}],"connections":[{"to":"two_to","from":"two_from","color":"orange","label":"subtract 2","style":"solid"},{"to":"three_to","from":"three_from","color":"green","label":"subtract 3","style":"solid"}]},"order":3,"title":"Solve each factor","description":"Subtract 2 from the first equation and 3 from the second. A1: both resulting solutions correct."}]}],"generatedAt":"2026-07-21T04:11:56.831Z","modelVersion":"gpt-5.6-terra","explanationVersion":"v3"},"options":[]}],"options":[],"explanation":null,"firstAttemptFullMarks":null,"walkthroughVideo":null},{"id":"b2cf389a-05e6-4dcf-ad80-4867651ec01c","revisionId":"5733bd6a-89fe-4d30-a8f4-56b434c3344f","questionNumber":"10","questionType":"LA","specification":"","difficulty":2,"difficultyBand":"medium","totalMarks":3,"sourceTitle":"Solving Quadratics","calculatorUse":null,"isCalculation":true,"parts":[{"id":"14e53afd-09e0-4da3-badf-bad984b1f9db","label":"0","content":"Solve $x^2 - 12x + 32 = 0$","markscheme":"- Factorises the quadratic: $(x - 4)(x - 8) = 0$ M2\n- Correct solutions: $x = 4$ or $x = 8$ A1","marks":3,"order":0,"markingRubric":{"totalMarks":3,"points":[{"id":"p1","marks":1,"description":"Identifies factors of 32 that sum to -12 (-4 and -8).","code":"M"},{"id":"p2","marks":1,"description":"Writes the quadratic in factorised form $(x-4)(x-8) = 0$.","code":"M"},{"id":"p3","marks":1,"description":"Final answers $x = 4$ and $x = 8$.","code":"A"}],"finalAnswers":["x = 4, x = 8"],"generatedAt":"2026-05-07T01:58:33.588Z","modelVersion":"gemini-3-flash-preview"},"tableImages":[],"explanation":{"methods":[{"id":"factorising","label":"Factorise then solve","steps":[{"type":"text","order":0,"title":"Choose the factor pair","content":"Find two numbers which multiply to $32$ and add to $12$: they are $4$ and $8$. Both signs are negative because the middle term is $-12x$, while the constant is positive.","highlights":[{"text":"$$x^2 - 12x + 32 = 0$","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"\\htmlData{anchor=original}{x^2-12x+32=0}"},{"latex":"\\htmlData{anchor=factorised}{(x-4)(x-8)=0}"}],"highlights":[{"color":"sky","style":"text-color-with-background","anchor":"factorised"}]},"order":1,"title":"Factorise the quadratic","description":"Find two numbers which multiply to 32 and add to 12. The correct factorisation earns the M2 marks."},{"type":"hyper_latex","block":{"nodes":[{"latex":"\\htmlData{anchor=first_factor}{x-4=0}"},{"latex":"\\htmlData{anchor=first_root}{x=4}"},{"latex":"\\htmlData{anchor=second_factor}{x-8=0}"},{"latex":"\\htmlData{anchor=second_root}{x=8}"}],"connections":[{"to":"first_root","from":"first_factor","color":"orange","label":"add 4","style":"solid"},{"to":"second_root","from":"second_factor","color":"orange","label":"add 8","style":"solid"}]},"order":2,"title":"Set each factor zero","description":"A product is zero only when at least one factor is zero, so set each factor equal to zero. These roots earn the A1 mark."}]}],"generatedAt":"2026-07-21T04:12:34.905Z","modelVersion":"gpt-5.6-terra","explanationVersion":"v3"},"options":[]}],"options":[],"explanation":null,"firstAttemptFullMarks":null,"walkthroughVideo":null},{"id":"2ada5dd1-ffd8-4c4a-a7cc-c334dd668bd1","revisionId":"2f67cbf7-898a-45be-9863-a7bd02d324da","questionNumber":"11","questionType":"LA","specification":"","difficulty":2,"difficultyBand":"medium","totalMarks":3,"sourceTitle":"Solving Quadratics","calculatorUse":null,"isCalculation":true,"parts":[{"id":"2add1e26-2ea0-4019-8beb-c40504dd8170","label":"0","content":"Solve $x^2 + 19x + 90 = 0$","markscheme":"- Factorises the quadratic: $(x + 9)(x + 10) = 0$ M2\n- Correct solutions: $x = -9$ or $x = -10$ A1","marks":3,"order":0,"markingRubric":{"totalMarks":3,"points":[{"id":"p1","marks":1,"description":"Identifies factors of 90 that sum to 19 (9 and 10).","code":"M"},{"id":"p2","marks":1,"description":"Writes the quadratic in factorised form $(x+9)(x+10) = 0$.","code":"M"},{"id":"p3","marks":1,"description":"Final answers $x = -9$ and $x = -10$.","code":"A"}],"finalAnswers":["x = -9, x = -10"],"generatedAt":"2026-05-07T01:58:33.588Z","modelVersion":"gemini-3-flash-preview"},"tableImages":[],"explanation":{"methods":[{"id":"factorising","label":"Factorising","steps":[{"type":"text","order":0,"title":"Find the factor pair","content":"To factorise, find two positive numbers that **multiply to** $90$ and **add to** $19$. They are $9$ and $10$.\n\nThe plus signs are needed because both terms in the quadratic are positive.","highlights":[{"text":"Solve $x^2 + 19x + 90 = 0$","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"\\htmlData{anchor=original}{x^2+19x+90=0}"},{"latex":"\\htmlData{anchor=factorised}{(x+9)(x+10)=0}"}],"highlights":[{"color":"sky","style":"text-color","anchor":"original"},{"color":"sky","style":"text-color-with-background","anchor":"factorised"}],"connections":[{"to":"factorised","from":"original","color":"sky","label":"factorise"}]},"order":1,"title":"Write the factors","description":"Put the two numbers into brackets with $x$. This factorisation earns the M2 mark."},{"type":"text","order":2,"title":"Use the zero product","content":"If two factors multiply to $0$, at least one factor must be $0$. So set each bracket equal to $0$ in turn."},{"type":"hyper_latex","block":{"nodes":[{"latex":"\\htmlData{anchor=first_bracket}{x+9=0}"},{"latex":"\\htmlData{anchor=first_solution}{x=-9}"},{"latex":"\\htmlData{anchor=second_bracket}{x+10=0}"},{"latex":"\\htmlData{anchor=second_solution}{x=-10}"}],"highlights":[{"color":"orange","style":"text-color-with-background","anchor":"first_solution"},{"color":"green","style":"text-color-with-background","anchor":"second_solution"}],"connections":[{"to":"first_solution","from":"first_bracket","color":"orange","label":"subtract 9"},{"to":"second_solution","from":"second_bracket","color":"green","label":"subtract 10"}]},"order":3,"title":"Solve each bracket","description":"Subtract the number in each bracket to find both possible values of $x$. 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Solving Quadratics

Question 4

Solving Quadratics Questions

Solving Quadratics

Question 4

Solving Quadratics Questions