Show that (3x−1)(4x+3)(x−9)=12x3−103x2−48x+27(3x - 1)(4x + 3)(x - 9) = 12x^3 - 103x^2 - 48x + 27(3x−1)(4x+3)(x−9)=12x3−103x2−48x+27 for all values of xxx.
Practise CIE IGCSE Maths Expanding Triple Brackets with exam-style questions for Core and Extended tier. 14 questions, matched to the CIE IGCSE Maths (0580) specification and written in Paper 1 and Paper 3 (Core) or Paper 2 and Paper 4 (Extended) style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.