Revision notes for CIE IGCSE Maths Probability Trees. Open the guide for explanations and worked examples. Written against the CIE IGCSE Maths (0580) specification, so the content matches what's examinable rather than general Maths background.
Revision notes for CIE IGCSE Maths Probability Trees. Open the guide for explanations and worked examples. Written against the CIE IGCSE Maths (0580) specification, so the content matches what's examinable rather than general Maths background.
A probability is a number from 0 to 1 that tells you how likely something is.
For counters, balls and cards, probability is usually:
number of successful outcomestotal number of outcomes\frac{\text{number of successful outcomes}}{\text{total number of outcomes}}total number of outcomesnumber of successful outcomesComplement
The complement of an event means “the event does not happen”. If the probability of an event is ppp, then the probability it does not happen is 1−p1 - p1−p.
For example, if the probability that a bus is late is 0.2, then the probability that it is not late is 0.8, because 0.2 + 0.8 = 1.
Finding a missing probability
A spinner lands on green with probability 38\frac{3}{8}83. It otherwise lands on purple. Find the probability it lands on purple.
The two outcomes are green and purple, so their probabilities must add to 1.
Subtract the green probability from 1:
1−38=581 - \frac{3}{8} = \frac{5}{8}1−83=85The probability of purple is 58\frac{5}{8}85.
Forgetting the total
If a bag has 5 red counters and 3 blue counters, the total is 8 counters. The probability of red is 58\frac{5}{8}85, not 53\frac{5}{3}35 or 55\frac{5}{5}55.
A probability tree is a diagram that shows a sequence of events. Each split shows the possible outcomes at that stage.
Probability tree
A probability tree is a branching diagram used for probability questions with more than one stage. A branch is one line on the tree, and each branch is labelled with the probability of that outcome.
At every split, the probabilities on the branches coming out must add to 1.
A two-stage tree is especially useful when something happens twice, such as choosing from two bags, playing two games, or checking two days.

Suppose one item is chosen from Bag A, and then one item is chosen from Bag B. The first split is for Bag A. From each of those branches, draw a second split for Bag B.
Two bags of coloured counters
Bag A contains 6 red counters and 4 blue counters. Bag B contains 2 red counters and 3 blue counters. One counter is chosen from each bag. Find the probability of choosing two blue counters.
Find the probabilities for Bag A. There are 10 counters in Bag A:
P(blue from A)=410=25P(\text{blue from A}) = \frac{4}{10} = \frac{2}{5}P(blue from A)=104=52Find the probabilities for Bag B. There are 5 counters in Bag B:
P(blue from B)=35P(\text{blue from B}) = \frac{3}{5}P(blue from B)=53On the tree, the first split is red from A or blue from A. The second split, from both branches, is red from B or blue from B.
To get two blue counters, follow the path “blue from A, then blue from B”.
Multiply along that path:
25×35=625\frac{2}{5} \times \frac{3}{5} = \frac{6}{25}52×53=256The probability of choosing two blue counters is 625\frac{6}{25}256.
Multiply along a path
When you want one complete route through the tree, multiply the probabilities on the branches in that route.
Two events are independent if the first event does not affect the probability of the second event.
For example, if someone plays a chess game and a backgammon game, winning the chess game does not change the given probability of winning the backgammon game.
Independent events
Events are independent when the outcome of one event does not change the probabilities for the next event.
Winning two independent games
Amir plays one game of table tennis and one game of darts. The probability he wins table tennis is 0.6. The probability he wins darts is 0.75. Find the probability he wins both games.
The first split is table tennis: win or not win.
Since P(win table tennis)=0.6P(\text{win table tennis}) = 0.6P(win table tennis)=0.6, the probability of not winning table tennis is 0.4.
The second split is darts: win or not win.
Since P(win darts)=0.75P(\text{win darts}) = 0.75P(win darts)=0.75, the probability of not winning darts is 0.25.
The event “wins both games” follows the path win, then win.
Multiply along the path:
0.6×0.75=0.450.6 \times 0.75 = 0.450.6×0.75=0.45The probability Amir wins both games is 0.45.
When probabilities can change
If the question says an item is taken and not replaced, the second set of probabilities may change. For example, after taking one red counter from a bag, there is one fewer red counter and one fewer counter in total.
Sometimes there is more than one way for the required event to happen.
For example, “different colours on two days” can happen in two ways:
These are different paths through the tree.
Add different successful paths
Multiply along each successful path first. Then add the path probabilities together.
Different choices on two days
Each morning, Sofia wears either a blue scarf or a white scarf. On any day, the probability she wears a blue scarf is 37\frac{3}{7}73. Find the probability she wears different coloured scarves on Monday and Tuesday.
First find the complement. The probability of wearing a white scarf is:
1−37=471 - \frac{3}{7} = \frac{4}{7}1−73=74There are two successful paths for “different colours”: blue then white, or white then blue.
Multiply along the blue then white path:
37×47=1249\frac{3}{7} \times \frac{4}{7} = \frac{12}{49}73×74=4912Multiply along the white then blue path:
47×37=1249\frac{4}{7} \times \frac{3}{7} = \frac{12}{49}74×73=4912Add the two successful paths:
1249+1249=2449\frac{12}{49} + \frac{12}{49} = \frac{24}{49}4912+4912=4924The probability she wears different coloured scarves is 2449\frac{24}{49}4924.
Adding too early
Do not add branch probabilities before you have found complete paths. For tree diagrams, usually multiply first along each path, then add the paths that match the question.
“At least one” means one or more. If there are two days, “late on at least one day” means:
You could add all three paths. But there is often a faster method: use the complement.
The opposite of “at least one late” is “none late”.
Fast method for at least one
For “at least one”, it is often quicker to calculate 1−P(none)1 - P(\text{none})1−P(none).
Late on at least one day
A train has probability 0.3 of being delayed on any day. Find the probability it is delayed on at least one of Saturday and Sunday.
Find the probability it is not delayed on a day:
1−0.3=0.71 - 0.3 = 0.71−0.3=0.7The complement of “delayed on at least one day” is “not delayed on either day”.
Multiply the probability of not delayed on Saturday by not delayed on Sunday:
0.7×0.7=0.490.7 \times 0.7 = 0.490.7×0.7=0.49Subtract from 1:
1−0.49=0.511 - 0.49 = 0.511−0.49=0.51The probability the train is delayed on at least one day is 0.51.
Not every split has only two branches. A game might have three possible outcomes: win, draw or lose.
The probabilities from one split must still add to 1.
Win, draw or lose
Nina plays two games. In any game, the probability she wins is 0.5, and the probability she draws is 0.2. Find the probability she wins both games.
Find the probability she loses one game. The three outcomes are win, draw and lose:
1−0.5−0.2=0.31 - 0.5 - 0.2 = 0.31−0.5−0.2=0.3For each game, the tree has three branches: win, draw and lose.
The event “wins both games” follows only one path: win in game 1, then win in game 2.
Multiply along this path:
0.5×0.5=0.250.5 \times 0.5 = 0.250.5×0.5=0.25The probability Nina wins both games is 0.25.
Check your branches
At each split, check that the branch probabilities add to 1. This catches many drawing errors before you start calculating.
Here is the main idea:
For example:
In the exam
Draw the tree neatly and label every branch with a probability.
Check each set of branches adds to 1 before calculating.
Circle or trace the successful path or paths.
Multiply along each path, then add if there is more than one successful path.
For “at least one”, consider using the complement: none.
Check yourself
Can you explain why the branches from the same point must add to 1?
If two paths both satisfy the question, do you multiply them together or add them after finding each path probability?
What is the complement of “at least one success”?
Test yourself with 5 quick questions on this guide. Answer them all correctly to complete it.
Test yourself on this topic, or move on to the next guide.
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