a=(−23)a = \begin{pmatrix} -2 \\ 3 \end{pmatrix}a=(−23) and b=(5−1)b = \begin{pmatrix} 5 \\ -1 \end{pmatrix}b=(5−1)
Write down as a column vector a+ba + ba+b.
Write down as a column vector 2a−b2a - b2a−b.
Translate the triangle by the vector (3−2)\begin{pmatrix} 3 \\ -2 \end{pmatrix}(3−2).

6 exam-style questions on CIE IGCSE Maths Vectors. Each one has a worked solution and a mark scheme showing where the marks go.