Revision notes for CIE IGCSE Maths Cylinders. Open the guide for explanations and worked examples. Written against the CIE IGCSE Maths (0580) specification, so the content matches what's examinable rather than general Maths background.
Revision notes for CIE IGCSE Maths Cylinders. Open the guide for explanations and worked examples. Written against the CIE IGCSE Maths (0580) specification, so the content matches what's examinable rather than general Maths background.
A cylinder is built from circles, so the key skills come from circle area and circumference.
Cylinder
A cylinder is a 3D solid with two equal, parallel circular faces joined by one curved surface. The radius is the distance from the centre of a circle to its edge, and the diameter is the distance all the way across the circle through the centre.
For a circle:
Using the diameter as the radius
If a question gives the diameter, halve it before using formulas with rrr. A diameter of 9 cm means the radius is 4.5 cm, not 9 cm.
Finding the radius and circular area
A circular end of a cylinder has diameter 12 cm. Find its radius and the area of the circular end in terms of π\piπ.
Halve the diameter to get the radius.
r=122=6r = \frac{12}{2} = 6r=212=6Use the circle area formula.
A=πr2=π×62A = \pi r^2 = \pi \times 6^2A=πr2=π×62Square the radius.
A=36πA = 36\piA=36πThe area of the circular end is 36π36\pi36π cm².
Volume tells you how much space a 3D solid takes up. For a cylinder, imagine stacking identical circular layers on top of each other.
Cylinder volume
The volume of a cylinder is the area of the circular base multiplied by the height, so V=πr2hV = \pi r^2hV=πr2h.
Here, VVV means volume, rrr means radius, and hhh means height.
Volume in terms of
A cylinder has radius 4 cm and height 10 cm. Work out its volume in terms of π\piπ.
Write down the formula.
V=πr2hV = \pi r^2hV=πr2hSubstitute radius 4 and height 10.
V=π×42×10V = \pi \times 4^2 \times 10V=π×42×10Square the radius, then multiply by the height.
V=π×16×10=160πV = \pi \times 16 \times 10 = 160\piV=π×16×10=160πThe volume is 160π160\pi160π cm³.
When the answer says in terms of
Leave π\piπ in your answer. Do not press the calculator’s π\piπ button unless the question asks for a decimal answer.
Volume with a diameter and rounding
A cylinder has diameter 8 cm and height 11.5 cm. Work out its volume correct to 1 decimal place.
Find the radius by halving the diameter.
r=82=4r = \frac{8}{2} = 4r=28=4Use the volume formula.
V=π×42×11.5V = \pi \times 4^2 \times 11.5V=π×42×11.5Calculate the value.
V=184π≈578.053V = 184\pi \approx 578.053V=184π≈578.053Round to 1 decimal place: the volume is 578.1 cm³.
Surface area is the total area of the outside faces of a 3D shape.
A net is a flat layout of a 3D shape. A closed cylinder’s net has:
The rectangle’s height is the cylinder height. Its width is the circumference of the circular base.

For a closed cylinder:
Closed or open cylinder?
The formula 2πr2+2πrh2\pi r^2 + 2\pi rh2πr2+2πrh is for a closed cylinder with both a top and a bottom. If a tank is open at the top, you would not include the top circle.
Total surface area from radius and height
A closed cylinder has radius 3 cm and height 9.5 cm. Find its total surface area correct to 1 decimal place.
Start with the closed-cylinder surface area formula.
TSA=2πr2+2πrh\text{TSA} = 2\pi r^2 + 2\pi rhTSA=2πr2+2πrhSubstitute radius 3 and height 9.5.
TSA=2π×32+2π×3×9.5\text{TSA} = 2\pi \times 3^2 + 2\pi \times 3 \times 9.5TSA=2π×32+2π×3×9.5Work out each part.
TSA=18π+57π=75π\text{TSA} = 18\pi + 57\pi = 75\piTSA=18π+57π=75πConvert to a decimal.
75π≈235.61975\pi \approx 235.61975π≈235.619The total surface area is 235.6 cm² to 1 decimal place.
Total surface area from diameter
A solid cylinder has diameter 10 cm and height 13 cm. Work out its total surface area correct to 3 significant figures.
Halve the diameter to find the radius.
r=102=5r = \frac{10}{2} = 5r=210=5Substitute into the total surface area formula.
TSA=2π×52+2π×5×13\text{TSA} = 2\pi \times 5^2 + 2\pi \times 5 \times 13TSA=2π×52+2π×5×13Simplify.
TSA=50π+130π=180π\text{TSA} = 50\pi + 130\pi = 180\piTSA=50π+130π=180πConvert to a decimal and round.
180π≈565.487180\pi \approx 565.487180π≈565.487The total surface area is 565 cm² to 3 significant figures.
A semi-cylinder is half a cylinder, usually made by cutting a cylinder lengthways.
For volume, a semi-cylinder is simply half the volume of the full cylinder:
V=12πr2LV = \frac{1}{2}\pi r^2LV=21πr2LHere, LLL is the length of the semi-cylinder.
For total surface area, think about each outside face:

Volume and surface area of a semi-cylinder
A semi-cylinder has radius 10 cm and length 40 cm. Find its volume and total surface area, each correct to 3 significant figures.
For volume, use half of the full-cylinder volume.
V=12π×102×40V = \frac{1}{2}\pi \times 10^2 \times 40V=21π×102×40Simplify the volume.
V=2000π≈6283.185V = 2000\pi \approx 6283.185V=2000π≈6283.185The volume is 6.28×1036.28 \times 10^36.28×103 cm³ to 3 significant figures.
For surface area, add the curved half, the flat rectangle, and the two semicircular ends.
TSA=πrL+2rL+πr2\text{TSA} = \pi rL + 2rL + \pi r^2TSA=πrL+2rL+πr2Substitute radius 10 and length 40.
TSA=π×10×40+2×10×40+π×102\text{TSA} = \pi \times 10 \times 40 + 2 \times 10 \times 40 + \pi \times 10^2TSA=π×10×40+2×10×40+π×102Simplify and round.
TSA=500π+800≈2370.796\text{TSA} = 500\pi + 800 \approx 2370.796TSA=500π+800≈2370.796The total surface area is 2.37×1032.37 \times 10^32.37×103 cm² to 3 significant figures.
A composite solid is a shape made from two or more simpler 3D solids. For volume, split it into shapes you know.
Half cylinder on a rectangular prism
A solid is made from a rectangular prism with a half-cylinder on top. It has width 4 m, total height 5 m, and length 9 m. Find the volume correct to 3 significant figures.
The half-cylinder sits across the width, so its diameter is 4 m and its radius is 2 m.
The rectangular prism height is the total height minus the radius of the half-cylinder.
5−2=35 - 2 = 35−2=3Find the prism volume.
4×3×9=1084 \times 3 \times 9 = 1084×3×9=108Find the semi-cylinder volume.
12π×22×9=18π\frac{1}{2}\pi \times 2^2 \times 9 = 18\pi21π×22×9=18πAdd the two volumes.
108+18π≈164.549108 + 18\pi \approx 164.549108+18π≈164.549The volume is 165 m³ to 3 significant figures.
Sometimes you are given the volume or surface area and asked to find a missing radius or height. Use the formula first, then solve the equation.
Finding a missing radius from volume
A cylinder has height 8 m and volume 288π288\pi288π m³. Find its radius.
Start with the volume formula.
V=πr2hV = \pi r^2hV=πr2hSubstitute the known values.
288π=πr2×8288\pi = \pi r^2 \times 8288π=πr2×8Divide both sides by π\piπ, then divide by 8.
288=8r2288 = 8r^2288=8r2Solve for r2r^2r2.
r2=36r^2 = 36r2=36Square root to find the positive radius.
r=6r = 6r=6The radius is 6 m.
Finding a missing height from surface area
A closed cylinder has radius 4 m and total surface area 112π112\pi112π m². Find its height.
Use the total surface area formula.
TSA=2πr2+2πrh\text{TSA} = 2\pi r^2 + 2\pi rhTSA=2πr2+2πrhSubstitute radius 4 and surface area 112π112\pi112π.
112π=2π×42+2π×4×h112\pi = 2\pi \times 4^2 + 2\pi \times 4 \times h112π=2π×42+2π×4×hSimplify.
112π=32π+8πh112\pi = 32\pi + 8\pi h112π=32π+8πhSubtract 32π32\pi32π from both sides.
80π=8πh80\pi = 8\pi h80π=8πhDivide by 8π8\pi8π.
h=10h = 10h=10The height is 10 m.
Cylinder questions often involve real-life units. Check whether all measurements are in the same unit before substituting into a formula.
Useful conversions:
Confusing square and cubic units
Surface area uses square units such as cm² or m². Volume uses cubic units such as cm³ or m³. Also, 1500 cm² is not 15 m²; since 1 m² is 10000 cm², 1500 cm² is 0.15 m².
Paint needed for closed cylindrical tanks
Four closed cylindrical tanks are to be painted. Each tank has diameter 50 cm and height 1.2 m. One pot of paint covers 3 m². How many pots are needed?
Convert the diameter to metres.
50 cm=0.5 m50\text{ cm} = 0.5\text{ m}50 cm=0.5 mFind the radius in metres.
r=0.52=0.25r = \frac{0.5}{2} = 0.25r=20.5=0.25Find the surface area of one closed tank.
TSA=2π×0.252+2π×0.25×1.2\text{TSA} = 2\pi \times 0.25^2 + 2\pi \times 0.25 \times 1.2TSA=2π×0.252+2π×0.25×1.2Simplify.
TSA=0.725π≈2.278\text{TSA} = 0.725\pi \approx 2.278TSA=0.725π≈2.278Find the total area for four tanks.
4×2.278≈9.1124 \times 2.278 \approx 9.1124×2.278≈9.112Divide by the coverage per pot.
9.112÷3≈3.0379.112 \div 3 \approx 3.0379.112÷3≈3.037You must buy 4 pots, because 3 pots would not cover enough area.
Rounding for practical answers
If you are buying pots of paint, packets, tiles, or containers, round up to the next whole number. You cannot buy 3.037 pots of paint.
Filling a cylindrical tank
A cylindrical tank has radius 10 cm and height 60 cm. Water flows in at 1.5 litres per minute. Find the time to fill the tank to the nearest minute.
Find the tank volume in cm³.
V=π×102×60=6000πV = \pi \times 10^2 \times 60 = 6000\piV=π×102×60=6000πConvert cm³ to litres by dividing by 1000.
6000π÷1000=6π6000\pi \div 1000 = 6\pi6000π÷1000=6πDivide by the flow rate.
6π÷1.5≈12.5666\pi \div 1.5 \approx 12.5666π÷1.5≈12.566Round to the nearest minute: it takes 13 minutes.
In the exam
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