Lithium and fluorine react to form the ionic compound lithium fluoride.
The chemical equation for this reaction is:
2Li+F2→2LiF 2\text{Li} + \text{F}_2 \rightarrow 2\text{LiF} 2Li+F2→2LiFWrite a word equation for this reaction.
Describe the changes in electronic configurations when lithium reacts with fluorine to form the ionic compound lithium fluoride (LiF\text{LiF}LiF). Include the electronic configurations of the atoms and the resulting ions, and show the charges on the ions. (Atomic numbers: Li=3\text{Li} = 3Li=3, F=9\text{F} = 9F=9)
Calculate the mass of lithium fluoride (LiF\text{LiF}LiF) that forms when 0.35 g0.35\text{ g}0.35 g of lithium reacts completely with fluorine. (Relative atomic masses, ArA_rAr: Li=7\text{Li} = 7Li=7, F=19\text{F} = 19F=19)
11 exam-style questions on Edexcel IGCSE Chemistry Ionic bonding. Each one has a worked solution and a mark scheme showing where the marks go.