Skip to content
MathsGenie logo
Open app

Course home

  1. IGCSE
  3. Chemistry Edexcel
  5. Question bank

Chemical formulae, equations and calculations

EasyMedium
1234567891011121314151617181920212223242526272829303132333435363738394041424344454647484950515253545556575859606162636465666768697071727374757677
Question 56

Hydrochloric acid can be neutralised by adding potassium hydroxide solution. The equation for the reaction is:

HCl+KOH→KCl+H2O \text{HCl} + \text{KOH} \rightarrow \text{KCl} + \text{H}_2\text{O} HCl+KOH→KCl+H2​O

A solution of hydrochloric acid has a concentration of 0.150 mol/dm3.

a.

Calculate the amount, in moles, of HCl\text{HCl}HCl in 40.0 cm3 of the hydrochloric acid solution.

[2]
b.

Calculate the volume of 0.250 mol/dm3 potassium hydroxide solution needed to exactly neutralise the hydrochloric acid. Give the unit.

[2]
c.

In another neutralisation reaction, a student uses 25.0 cm3 of 0.400 mol/dm3 aqueous potassium hydroxide solution.

Calculate the mass of potassium hydroxide contained in this solution. [Relative atomic masses, ArA_rAr​: H=1\text{H} = 1H=1, O=16\text{O} = 16O=16, K=39\text{K} = 39K=39]

[3]

Chemical formulae, equations and calculations Questions

  1. IGCSE
  2. /Chemistry
  3. /Chemical formulae, equations and calculations