Skip to content
MathsGenie logo
Open app

Course home

  1. IGCSE
  2. Chemistry Edexcel
  3. Question bank

Chemical formulae, equations and calculations

EasyMedium
1234567891011121314151617181920212223242526272829303132333435363738394041424344454647484950515253545556575859606162636465666768697071727374757677
Question 47

Antacid tablets containing calcium carbonate, CaCO3\text{CaCO}_3CaCO3​, can be used to neutralise excess hydrochloric acid in the stomach.

The equation for the reaction is:

CaCO3(s)+2HCl(aq)→CaCl2(aq)+H2O(l)+CO2(g) \text{CaCO}_3(\text{s}) + 2\text{HCl}(\text{aq}) \rightarrow \text{CaCl}_2(\text{aq}) + \text{H}_2\text{O}(\text{l}) + \text{CO}_2(\text{g}) CaCO3​(s)+2HCl(aq)→CaCl2​(aq)+H2​O(l)+CO2​(g)

A student investigates how much calcium carbonate is needed to neutralise 150 cm3 of hydrochloric acid with a concentration of 0.120 mol/dm3.

He uses 1.0 g of calcium carbonate.

a.

Calculate the amount, in moles, of HCl\text{HCl}HCl in the hydrochloric acid.

[2]
b.

Calculate the amount, in moles, of CaCO3\text{CaCO}_3CaCO3​ used by the student. [Mr of CaCO3=100M_{\text{r}}\text{ of }\text{CaCO}_3 = 100Mr​ of CaCO3​=100]

[2]
c.

Explain whether the student used the right amount of calcium carbonate to neutralise the hydrochloric acid.

[3]

Chemical formulae, equations and calculations Questions

  1. IGCSE
  2. /Chemistry
  3. /Chemical formulae, equations and calculations