The equation shows the reaction of aluminium with dilute hydrochloric acid:
2Al(s)+6HCl(aq)→2AlCl3(aq)+3H2(g) 2\text{Al(s)} + 6\text{HCl(aq)} \rightarrow 2\text{AlCl}_3\text{(aq)} + 3\text{H}_2\text{(g)} 2Al(s)+6HCl(aq)→2AlCl3(aq)+3H2(g)A sample of aluminium of mass 0.162 g0.162\text{ g}0.162 g reacts completely with excess hydrochloric acid.
Calculate the volume of hydrogen gas, in cm3\text{cm}^3cm3, produced at room temperature and pressure (rtp).
The volume of one mole of a gas at rtp is 24 000 cm3. Note: Ar(Al)=27. \text{The volume of one mole of a gas at rtp is } 24\,000\text{ cm}^3. \text{ Note: } A_r(\text{Al}) = 27. The volume of one mole of a gas at rtp is 24000 cm3. Note: Ar(Al)=27.
