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Chemical formulae, equations and calculations

Chemical formulae, equations and calculations

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Question 39

Chromium is a transition metal that can be extracted from its chief ore, chromite, in a multi-stage process.

a.

A sample of chromite ore has the following composition by mass:

Fe=24.9%,Cr=46.5%,O=28.6% \text{Fe} = 24.9\%, \quad \text{Cr} = 46.5\%, \quad \text{O} = 28.6\% Fe=24.9%,Cr=46.5%,O=28.6%

Show by calculation that the empirical formula of this ore is FeCr2O4\text{FeCr}_2\text{O}_4FeCr2​O4​. [Relative atomic masses, ArA_rAr​: O=16.0\text{O} = 16.0O=16.0, Cr=52.0\text{Cr} = 52.0Cr=52.0, Fe=55.8\text{Fe} = 55.8Fe=55.8]

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b.

In one extraction method, chromium(III) oxide (Cr2O3\text{Cr}_2\text{O}_3Cr2​O3​) is reacted with aluminium at high temperatures:

Cr2O3+2Al→2Cr+Al2O3 \text{Cr}_2\text{O}_3 + 2\text{Al} \rightarrow 2\text{Cr} + \text{Al}_2\text{O}_3 Cr2​O3​+2Al→2Cr+Al2​O3​

Explain which element has been oxidised in this reaction.

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c.

Describe the bonding in chromium metal.

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d.

Explain why chromium metal conducts electricity.

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Markscheme

Chemical formulae, equations and calculations Questions

  1. IGCSE
  2. /Chemistry
  3. /Chemical formulae, equations and calculations

80 exam-style questions on Edexcel IGCSE Chemistry Chemical formulae, equations and calculations. Each one has a worked solution and a mark scheme showing where the marks go.

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