Calcium reacts with dilute hydrochloric acid. The equation for the reaction is:
Ca(s)+2HCl(aq)→CaCl2(aq)+H2(g) \text{Ca(s)} + 2\text{HCl(aq)} \rightarrow \text{CaCl}_2\text{(aq)} + \text{H}_2\text{(g)} Ca(s)+2HCl(aq)→CaCl2(aq)+H2(g)0.120 g of calcium was added to 50.0 cm3 of 0.150 mol/dm3 hydrochloric acid. (Assume the relative atomic mass of calcium, Ar(Ca)=40.0A_r(\text{Ca}) = 40.0Ar(Ca)=40.0). Calculate the amount, in moles, of calcium used.
Calculate the amount, in moles, of HCl\text{HCl}HCl in the 50.0 cm3 of hydrochloric acid.
Use your answers from (a) to determine which of the reactants is in excess. Show your reasoning.
