Skip to content
MathsGenie logo
Quick links
Open app

Course home

  1. IGCSE
  2. Chemistry Edexcel
  3. Question bank

Chemical formulae, equations and calculations

EasyMedium
1234567891011121314151617181920212223242526272829303132333435363738394041424344454647484950515253545556575859606162636465666768697071727374757677787980818283848586
Question 19

An environmental chemist is investigating the neutralisation of acidic run-off from an industrial site. The run-off contains hydrochloric acid, HCl\text{HCl}HCl.

The chemist uses solid sodium carbonate, Na2CO3\text{Na}_2\text{CO}_3Na2​CO3​, to neutralise the acid according to the equation:

Na2CO3(s)+2HCl(aq)→2NaCl(aq)+H2O(l)+CO2(g) \text{Na}_2\text{CO}_3(\text{s}) + 2\text{HCl}(\text{aq}) \rightarrow 2\text{NaCl}(\text{aq}) + \text{H}_2\text{O}(\text{l}) + \text{CO}_2(\text{g}) Na2​CO3​(s)+2HCl(aq)→2NaCl(aq)+H2​O(l)+CO2​(g)

In a laboratory simulation, the chemist tests a 250 cm3250\text{ cm}^3250 cm3 sample of the run-off which has a hydrochloric acid concentration of 0.160 mol/dm30.160\text{ mol/dm}^30.160 mol/dm3.

They add 2.65 g2.65\text{ g}2.65 g of solid sodium carbonate to the sample.

a.

Calculate the amount, in moles, of HCl\text{HCl}HCl in the run-off sample.

[2]
b.

Calculate the amount, in moles, of Na2CO3\text{Na}_2\text{CO}_3Na2​CO3​ added to the sample. [Mr of Na2CO3=106M_{\text{r}}\text{ of }\text{Na}_2\text{CO}_3 = 106Mr​ of Na2​CO3​=106]

[2]
c.

Explain whether the chemist added the correct amount of sodium carbonate to exactly neutralise the hydrochloric acid.

[3]

Chemical formulae, equations and calculations Questions

  1. IGCSE
  2. /Chemistry
  3. /Chemical formulae, equations and calculations