Sodium thiosulfate solution and dilute hydrochloric acid react together slowly to form a precipitate of sulfur, which makes the mixture cloudy.
The equation for the reaction is:
Na2S2O3(aq)+2HCl(aq)→2NaCl(aq)+H2O(l)+S(s)+SO2(g) \text{Na}_2\text{S}_2\text{O}_3(\text{aq}) + 2\text{HCl}(\text{aq}) \rightarrow 2\text{NaCl}(\text{aq}) + \text{H}_2\text{O}(\text{l}) + \text{S}(\text{s}) + \text{SO}_2(\text{g}) Na2S2O3(aq)+2HCl(aq)→2NaCl(aq)+H2O(l)+S(s)+SO2(g)A student performs an experiment using the following conditions:
Calculate the mass of sulfur dioxide, SO2\text{SO}_2SO2, formed in this experiment. (ArA_rAr: O=16\text{O} = 16O=16, S=32\text{S} = 32S=32)
The solubility of sulfur dioxide at room temperature is 90 g/dm3. Use this information to explain whether any sulfur dioxide gas escapes from the flask during the experiment.
