Vitamin C (ascorbic acid, C6H8O6\text{C}_6\text{H}_8\text{O}_6C6H8O6) is an essential nutrient found in fruit juices. The level of Vitamin C in a fruit juice can be determined by titration with aqueous iodine, I2(aq)\text{I}_2(aq)I2(aq).
A chemist titrated a 20.0 cm3 sample of orange juice, which reacted with exactly 12.00 cm3 of 0.0050 mol/dm3 aqueous iodine.
The equation for the reaction is:
C6H8O6(aq)+I2(aq)→C6H6O6(aq)+2I−(aq)+2H+(aq) \text{C}_6\text{H}_8\text{O}_6(aq) + \text{I}_2(aq) \rightarrow \text{C}_6\text{H}_6\text{O}_6(aq) + 2\text{I}^-(aq) + 2\text{H}^+(aq) C6H8O6(aq)+I2(aq)→C6H6O6(aq)+2I−(aq)+2H+(aq)Calculate the amount, in moles, of iodine in 12.00 cm3 of a 0.0050 mol/dm3 solution.
Deduce the amount, in moles, of Vitamin C in the 20.0 cm3 sample of orange juice.
Calculate the concentration, in mol/dm3\text{mol/dm}^3mol/dm3, of Vitamin C in the orange juice.
Calculate the concentration, in g/dm3\text{g/dm}^3g/dm3, of Vitamin C in the orange juice. (Relative atomic masses: H=1.0\text{H} = 1.0H=1.0, C=12.0\text{C} = 12.0C=12.0, O=16.0\text{O} = 16.0O=16.0)
A certain brand of fruit juice must contain at least 0.45 g/dm3 of Vitamin C to be marketed as "high in Vitamin C".
Use the value you have calculated in (d) to state whether this juice can be marketed as "high in Vitamin C".
