A car of mass 1200 kg travels a distance of d d\,d metres up a straight hill inclined at an angle θ \theta\,θ to the horizontal, where sinθ=115\displaystyle \sin \theta = \frac{1}{15}sinθ=151.
The work done against gravity as the car climbs this distance is 78.4 kJ.
Taking g=9.8 m/s2g = 9.8\text{ m/s}^2g=9.8 m/s2, find the value of ddd.
6.7 m6.7\text{ m}6.7 m
98 m98\text{ m}98 m
100 m100\text{ m}100 m
150 m150\text{ m}150 m