0.50 kg of water is heated from 20 ∘C20\ ^{\circ}\text{C}20 ∘C to 60 ∘C60\ ^{\circ}\text{C}60 ∘C.
The specific heat capacity of water is 4200 J/kg ∘C4200\ \text{J/kg}\ ^{\circ}\text{C}4200 J/kg ∘C.
Use the equation: change in thermal energy=mass×specific heat capacity×change in temperature\text{change in thermal energy} = \text{mass} \times \text{specific heat capacity} \times \text{change in temperature}change in thermal energy=mass×specific heat capacity×change in temperature
What is the change in thermal energy of the water?
42 000 J42\,000\ \text{J}42000 J
84 000 J84\,000\ \text{J}84000 J
126 000 J126\,000\ \text{J}126000 J
168 000 J168\,000\ \text{J}168000 J
44 exam-style questions on OCR GCSE Physics 7.1 Work done, covering 7.1.1 Conservation of energy in a closed system, 7.1.2 Energy stores and transfers, 7.1.3 Energy changes by heating, forces and current, 7.1.4 Quantifying energy transfers in a system, and 7.1.5 Kinetic, elastic and gravitational potential energy. Each one has a worked solution and a mark scheme showing where the marks go.