A force of 25 N pushes a trolley a distance of 4.0 m in the direction of the force.
Use the equation: work done=force×distance\text{work done} = \text{force} \times \text{distance}work done=force×distance
How much work is done on the trolley?
6.25 J6.25\ \text{J}6.25 J
21 J21\ \text{J}21 J
29 J29\ \text{J}29 J
100 J100\ \text{J}100 J
44 exam-style questions on OCR GCSE Physics 7.1 Work done, covering 7.1.1 Conservation of energy in a closed system, 7.1.2 Energy stores and transfers, 7.1.3 Energy changes by heating, forces and current, 7.1.4 Quantifying energy transfers in a system, and 7.1.5 Kinetic, elastic and gravitational potential energy. Each one has a worked solution and a mark scheme showing where the marks go.