An industrial conveyor belt lifts luggage with a total mass of 300 kg through a vertical height h=8.0 mh = 8.0\text{ m}h=8.0 m every minute at a constant speed, as shown in the diagram below.
The electric motor driving the conveyor belt has an efficiency of 0.70.
Using g=9.8 m s−2g = 9.8\text{ m s}^{-2}g=9.8 m s−2, calculate the input electrical power of the motor.
274.4 W274.4\text{ W}274.4 W
392.0 W392.0\text{ W}392.0 W
560.0 W560.0\text{ W}560.0 W
33,600 W33,600\text{ W}33,600 W