A skateboarder starts at an initial velocity of 0.0 m/s and accelerates at 1.5 m/s2 for a distance of 25 m.
What is the final velocity of the skateboarder?
Use the equation: (final velocity)2−(initial velocity)2=2×acceleration×distance\text{(final velocity)}^2 - \text{(initial velocity)}^2 = 2 \times \text{acceleration} \times \text{distance}(final velocity)2−(initial velocity)2=2×acceleration×distance
6.1 m/s6.1\text{ m/s}6.1 m/s
8.7 m/s8.7\text{ m/s}8.7 m/s
37.5 m/s37.5\text{ m/s}37.5 m/s
75 m/s75\text{ m/s}75 m/s
Practise OCR GCSE Physics Motion with exam-style questions for Foundation and Higher tier. 97 questions, matched to the OCR GCSE Physics (J249) specification and written in Paper 1 and Paper 2 (Foundation Tier) or Paper 3 and Paper 4 (Higher Tier) style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.