An environmental monitoring satellite is launched into a low Earth polar orbit at an altitude of 630 km above the Earth's surface to scan global forest cover.
Assume the Earth is a uniform sphere with radius RE=6.37×106 mR_{\text{E}} = 6.37 \times 10^6\text{ m}RE=6.37×106 m and mass ME=5.97×1024 kgM_{\text{E}} = 5.97 \times 10^{24}\text{ kg}ME=5.97×1024 kg.
Which of the following correctly identifies the orbital period of the satellite and the number of complete orbits it completes in a 24-hour period?
(G=6.67×10−11 N m2 kg−2G = 6.67 \times 10^{-11}\text{ N m}^2\text{ kg}^{-2}G=6.67×10−11 N m2 kg−2)
Period≈84 minutes\text{Period} \approx 84\text{ minutes}Period≈84 minutes; Complete orbits=17\text{Complete orbits} = 17Complete orbits=17
Period≈88 minutes\text{Period} \approx 88\text{ minutes}Period≈88 minutes; Complete orbits=16\text{Complete orbits} = 16Complete orbits=16
Period≈97 minutes\text{Period} \approx 97\text{ minutes}Period≈97 minutes; Complete orbits=14\text{Complete orbits} = 14Complete orbits=14
Period≈16 minutes\text{Period} \approx 16\text{ minutes}Period≈16 minutes; Complete orbits=92\text{Complete orbits} = 92Complete orbits=92