A transformer has 400 turns on its primary coil and 1200 turns on its secondary coil.
The primary coil is connected to an alternating current supply with a peak potential difference of 12 V.
Calculate the peak potential difference across the secondary coil.
Use the equation
VPVS=NPNS\displaystyle \frac{V_P}{V_S} = \frac{N_P}{N_S}VSVP=NSNP
The secondary coil is connected to a resistor. The peak current in the secondary coil is 0.20 A.
The transformer is 100% efficient.
Calculate the peak current in the primary coil.
Use the equation
VP×IP=VS×ISV_P \times I_P = V_S \times I_SVP×IP=VS×IS
The iron core is replaced by a plastic core of the same shape.
Explain the effect on the potential difference across the secondary coil.
108 exam-style questions on Edexcel GCSE Physics 13.2 Transformers and the National Grid, covering 13.2.1 Transformers and induction, 13.2.2 The transformer turns-ratio equation, 13.2.3 The National Grid, 13.2.4 The transformer power equation, and 13.2.5 Advantages of high-voltage transmission. Each one has a worked solution and a mark scheme showing where the marks go.