An illuminated information panel uses a transformer to supply a lamp. The primary coil is connected to a 230 V alternating supply.
| Quantity | Value |
|---|---|
| Potential difference across primary coil | 230 V |
| Number of turns on primary coil | 920 |
| Number of turns on secondary coil | 48 |
Use the equation
VpVs=NpNs\dfrac{V_{\mathrm{p}}}{V_{\mathrm{s}}}=\dfrac{N_{\mathrm{p}}}{N_{\mathrm{s}}}VsVp=NsNp
Identify whether the transformer is a step-up transformer or a step-down transformer.
Calculate the potential difference across the secondary coil.
The current in the secondary coil is 1.5 A.
Calculate the power delivered to the lamp.
Use the equation
P=V×IP=V\times IP=V×I
The transformer is 100% efficient.
Calculate the current in the primary coil.
Use your answer to part (c) and the equation
I=PVI=\dfrac{P}{V}I=VP
108 exam-style questions on Edexcel GCSE Physics 13.2 Transformers and the National Grid, covering 13.2.1 Transformers and induction, 13.2.2 The transformer turns-ratio equation, 13.2.3 The National Grid, 13.2.4 The transformer power equation, and 13.2.5 Advantages of high-voltage transmission. Each one has a worked solution and a mark scheme showing where the marks go.