Figure 1 shows a horizontal conducting copper rod suspended by two vertical wires, completing an electrical circuit. The rod is situated within a uniform vertical magnetic field between the poles of a magnet.
The magnetic flux density of the uniform magnetic field is 0.45 T0.45\text{ T}0.45 T.
The current flowing through the rod is 3.6 A.
The active length of the copper rod within the magnetic field is 15 cm.
Calculate the magnetic force acting on the rod.
Use the equation:
F=B×I×l F = B \times I \times l F=B×I×l