The Big Bang, red-shift and the expanding Universe

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Question 21
Easy

The speed of light is 3.00 × 108 m/s.

Comparison of absorption spectra showing a laboratory reference with a line at 600 nm and the spectrum of Galaxy G with a wavelength shift of 12 nm.

At Earth, the wavelength of a spectral line detected from the distant galaxy G\mathbf{G}G is different from the wavelength emitted in a stationary laboratory.

The difference in wavelength (wavelength shift) is 12 nm12\text{ nm}12 nm.

The rest wavelength that the source emits is 600 nm600\text{ nm}600 nm.

Calculate the recessional velocity of galaxy G\mathbf{G}G.

Use the equation:

velocity of galaxy G=speed of light×wavelength shiftrest wavelength emitted \text{velocity of galaxy } \mathbf{G} = \frac{\text{speed of light} \times \text{wavelength shift}}{\text{rest wavelength emitted}} velocity of galaxy G=rest wavelength emittedspeed of light×wavelength shift​

Give your answer in standard form.

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The Big Bang, red-shift and the expanding Universe Questions

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