The Big Bang, red-shift and the expanding Universe

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Question 1
Easy

The velocity of sound in air is 340 m/s.

Diagram showing a stationary sound detector, R, on the left, and a moving object, P, on the right. Object P is moving away from detector R to the right, emitting sound waves. The wave crests are spaced further apart behind the object P as it moves away.

At the stationary detector R\mathbf{R}R, the wavelength of the sound detected is different from the wavelength emitted by the moving object P\mathbf{P}P.

The difference in wavelength is 0.06 m.

The wavelength that object P\mathbf{P}P emits is 1.20 m.

Calculate the velocity of P\mathbf{P}P.

Use the equation:

velocity of P=velocity of sound×difference in wavelengthwavelength P emits \text{velocity of } \mathbf{P} = \frac{\text{velocity of sound} \times \text{difference in wavelength}}{\text{wavelength } \mathbf{P} \text{ emits}} velocity of P=wavelength P emitsvelocity of sound×difference in wavelength​
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The Big Bang, red-shift and the expanding Universe Questions

  1. GCSE
  2. /Physics
  3. /The Big Bang, red-shift and the expanding Universe