A cyclist rides down a straight hill.
The velocity of the cyclist increases from 4.0 m/s to 10 m/s over a distance of 42 m.
Calculate the acceleration of the cyclist.
Use the equation
v2−u2=2×a×xv^2 - u^2 = 2 \times a \times xv2−u2=2×a×x
Calculate the time taken for the cyclist to travel the 42 m.
At the bottom of the hill the cyclist brakes and stops from 10 m/s in a distance of 5.0 m.
Calculate the deceleration of the cyclist.
96 exam-style questions on Edexcel GCSE Physics 2.2 Speed, velocity and acceleration, covering 2.2.1 Speed and distance–time graphs, 2.2.2 Acceleration and the uniform-acceleration equation, 2.2.3 Velocity–time graphs, and 2.2.4 Measuring speed, typical speeds and free-fall acceleration. Each one has a worked solution and a mark scheme showing where the marks go.