A scientific sensor probe is released from rest from a stationary research balloon in the atmosphere of an exoplanet.
The probe falls vertically under gravity.
Calculate the distance the probe has fallen when its velocity reaches 12 m/s.
Use the equation:
v2−u2=2as v^2 - u^2 = 2as v2−u2=2asAssume the acceleration due to gravity on this planet is a=4.8 m/s2a = 4.8\text{ m/s}^2a=4.8 m/s2.
53 exam-style questions on Edexcel GCSE Physics 2.2 Speed, velocity and acceleration. Each one has a worked solution and a mark scheme showing where the marks go.