A cyclist is riding down a hill at 3.5 m/s.
The cyclist accelerates uniformly for 8.0 s.
The speed of the cyclist increases to 19.5 m/s.
Calculate the acceleration of the cyclist.
Use the equation:
a=v−ut a = \frac{v - u}{t} a=tv−u53 exam-style questions on Edexcel GCSE Physics 2.2 Speed, velocity and acceleration, covering 2.2.1 Speed and distance–time graphs, 2.2.2 Acceleration and the uniform-acceleration equation, 2.2.3 Velocity–time graphs, and 2.2.4 Measuring speed, typical speeds and free-fall acceleration. Each one has a worked solution and a mark scheme showing where the marks go.