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10.2 Resistance

10.2 Resistance

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Question 31

The unit of electrical resistance is the ohm (Ω\OmegaΩ).

Starting with the definition of electrical resistance, we can obtain an equivalent unit as V A−1\text{V A}^{-1}V A−1 (volt per ampere).

Using resistance=potential differencecurrent\displaystyle \text{resistance} = \frac{\text{potential difference}}{\text{current}}resistance=currentpotential difference​

unit of resistance=unit of potential differenceunit of current=V A−1\displaystyle \text{unit of resistance} = \frac{\text{unit of potential difference}}{\text{unit of current}} = \text{V A}^{-1}unit of resistance=unit of currentunit of potential difference​=V A−1

The unit of electrical resistivity is the ohm-metre (Ω⋅m\Omega\cdot\text{m}Ω⋅m).

Explain how, starting with the definition of electrical resistivity, we may obtain this equivalent unit of resistivity in terms of the ohm (Ω\OmegaΩ) and the metre (m\text{m}m).

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Markscheme

10.2 Resistance Questions

  1. GCSE
  2. /Physics
  3. /10.2 Resistance

59 exam-style questions on Edexcel GCSE Physics 10.2 Resistance. Each one has a worked solution and a mark scheme showing where the marks go.

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