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10.2 Resistance

10.2 Resistance

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Question 24

The unit of potential difference is the volt.

Starting with the definition of potential difference, we can obtain an equivalent unit as J/C\text{J/C}J/C (joule per coulomb).

Using potential difference=work done (or energy transferred)charge\displaystyle \text{potential difference} = \frac{\text{work done (or energy transferred)}}{\text{charge}}potential difference=chargework done (or energy transferred)​

unit of potential difference=unit of energyunit of charge=J/C\displaystyle \text{unit of potential difference} = \frac{\text{unit of energy}}{\text{unit of charge}} = \text{J/C}unit of potential difference=unit of chargeunit of energy​=J/C

The unit of electrical resistance is the ohm (Ω\OmegaΩ).

Explain how, starting with the definition of electrical resistance, we may obtain an equivalent unit of resistance.

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Markscheme

10.2 Resistance Questions

  1. GCSE
  2. /Physics
  3. /10.2 Resistance

59 exam-style questions on Edexcel GCSE Physics 10.2 Resistance. Each one has a worked solution and a mark scheme showing where the marks go.

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