A student proposes this equation for a decay.
83214Bi→82210Pb+24He++10e {}^{214}_{83}\mathrm{Bi}\rightarrow{}^{210}_{82}\mathrm{Pb}+{}^{4}_{2}\mathrm{He}+{}^{0}_{+1}\mathrm{e} 83214Bi→82210Pb+24He++10eWhich single change balances the equation?
Replace 24He{}^{4}_{2}\mathrm{He}24He with 01n{}^{1}_{0}\mathrm{n}01n.
Replace 83214Bi{}^{214}_{83}\mathrm{Bi}83214Bi with 83213Bi{}^{213}_{83}\mathrm{Bi}83213Bi.
Replace +10e{}^{0}_{+1}\mathrm{e}+10e with 00γ{}^{0}_{0}\gamma00γ.
Replace +10e{}^{0}_{+1}\mathrm{e}+10e with −10e{}^{0}_{-1}\mathrm{e}−10e.