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6 Radioactivity

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Question 26
F

Strontium-90 decays by beta minus decay to form yttrium-90.

The equation for this decay is

3890Sr→3990Y+bae {}^{90}_{38}\mathrm{Sr} \rightarrow {}^{90}_{39}\mathrm{Y} + {}^{a}_{b}\mathrm{e} 3890​Sr→3990​Y+ba​e
a.

Give the values of a a\,a and bbb.

[2]
b.

Calculate the number of neutrons in a yttrium-90 nucleus.

[2]
c.

A particle is emitted from the nucleus in beta minus decay.

Explain why the mass number of the nucleus does not change.

[2]
d.

Yttrium-90 also decays by beta minus decay.

Give the atomic number of the nucleus that is formed.

[1]
Markscheme

6 Radioactivity Questions

  1. GCSE
  2. /Physics
  3. /6 Radioactivity

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