A materials-testing laboratory analyses a sample containing aluminium-26. One nuclear change is recorded as
1326Al→1226Mg+X {}^{26}_{13}\mathrm{Al}\rightarrow{}^{26}_{12}\mathrm{Mg}+\mathrm{X} 1326Al→1226Mg+XThe table shows the possible identities of X\mathrm{X}X.
| Particle | Nuclear symbol |
|---|---|
| beta-minus particle | −10e{}^{0}_{-1}\mathrm{e}−10e |
| positron | +10e{}^{0}_{+1}\mathrm{e}+10e |
| gamma ray | 00γ{}^{0}_{0}\gamma00γ |
| proton | 11p{}^{1}_{1}\mathrm{p}11p |
Which particle completes the nuclear equation?
a positron
a proton
a gamma ray
a beta-minus particle