Cobalt-60 decays to nickel-60. The nickel nucleus then emits gamma radiation.
The equation for the decays is
2760Co→2860Ni+−10e+00γ {}^{60}_{27}\mathrm{Co} \rightarrow {}^{60}_{28}\mathrm{Ni} + {}^{0}_{-1}\mathrm{e} + {}^{0}_{0}\gamma 2760Co→2860Ni+−10e+00γShow that the equation is balanced for mass number and for charge.
Explain why a gamma ray is emitted after the beta minus particle.
Explain why the emission of gamma radiation has no effect on the atomic number of the nucleus.
Determine the number of neutrons in a cobalt-60 nucleus and in a nickel-60 nucleus.
120 exam-style questions on Edexcel GCSE Physics 6.3 Nuclear equations and decay, covering 6.3.1 Beta-minus and beta-plus decay, 6.3.2 Effects of decay on the nucleus, and 6.3.3 Balancing nuclear equations. Each one has a worked solution and a mark scheme showing where the marks go.