Strontium-90 decays by beta minus decay to form yttrium-90.
The equation for this decay is
3890Sr→3990Y+bae {}^{90}_{38}\mathrm{Sr} \rightarrow {}^{90}_{39}\mathrm{Y} + {}^{a}_{b}\mathrm{e} 3890Sr→3990Y+baeGive the values of a a\,a and bbb.
Calculate the number of neutrons in a yttrium-90 nucleus.
A particle is emitted from the nucleus in beta minus decay.
Explain why the mass number of the nucleus does not change.
Yttrium-90 also decays by beta minus decay.
Give the atomic number of the nucleus that is formed.
120 exam-style questions on Edexcel GCSE Physics 6.3 Nuclear equations and decay, covering 6.3.1 Beta-minus and beta-plus decay, 6.3.2 Effects of decay on the nucleus, and 6.3.3 Balancing nuclear equations. Each one has a worked solution and a mark scheme showing where the marks go.