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6.3 Nuclear equations and decay

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Question 48

Deduce which nucleus is formed when potassium-40 absorbs an electron.

Use the nuclear equation below and the list of proton (atomic) numbers to help you:

  • Argon (Ar): proton number = 18
  • Potassium (K): proton number = 19
  • Calcium (Ca): proton number = 20
11p+−10e⟶01n {}^1_1\text{p} + {}^0_{-1}\text{e} \longrightarrow {}^1_0\text{n} 11​p+−10​e⟶01​n
A

argon-40

B

potassium-39

C

calcium-40

D

argon-39

Markscheme

6.3 Nuclear equations and decay Questions

  1. GCSE
  2. /Physics
  3. /6.3 Nuclear equations and decay

90 exam-style questions on Edexcel GCSE Physics 6.3 Nuclear equations and decay, covering 6.3.1 Beta-minus and beta-plus decay, 6.3.2 Effects of decay on the nucleus, and 6.3.3 Balancing nuclear equations. Each one has a worked solution and a mark scheme showing where the marks go.

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