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6.3 Nuclear equations and decay

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Question 39
H

A student proposes this equation for a decay.

83214Bi→82210Pb+24He++10e {}^{214}_{83}\mathrm{Bi}\rightarrow{}^{210}_{82}\mathrm{Pb}+{}^{4}_{2}\mathrm{He}+{}^{0}_{+1}\mathrm{e} 83214​Bi→82210​Pb+24​He++10​e

Which single change balances the equation?

[1]
A

Replace 24He{}^{4}_{2}\mathrm{He}24​He with 01n{}^{1}_{0}\mathrm{n}01​n.

B

Replace 83214Bi{}^{214}_{83}\mathrm{Bi}83214​Bi with 83213Bi{}^{213}_{83}\mathrm{Bi}83213​Bi.

C

Replace +10e{}^{0}_{+1}\mathrm{e}+10​e with 00γ{}^{0}_{0}\gamma00​γ.

D

Replace +10e{}^{0}_{+1}\mathrm{e}+10​e with −10e{}^{0}_{-1}\mathrm{e}−10​e.

Markscheme

6.3 Nuclear equations and decay Questions

  1. GCSE
  2. /Physics
  3. /6.3 Nuclear equations and decay

120 exam-style questions on Edexcel GCSE Physics 6.3 Nuclear equations and decay, covering 6.3.1 Beta-minus and beta-plus decay, 6.3.2 Effects of decay on the nucleus, and 6.3.3 Balancing nuclear equations. Each one has a worked solution and a mark scheme showing where the marks go.

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