A display stand transfers a normal force of 450 N to the floor. The underside of its base is a rectangle measuring 15 cm by 6.0 cm. The floor covering must not be subjected to a pressure greater than 6.0 × 104 Pa. What conclusion should be made about using the stand on this floor covering?
5.0×102 Pa5.0\times10^2\ \mathrm{Pa}5.0×102 Pa, so the stand can be used.
5.0×105 Pa5.0\times10^5\ \mathrm{Pa}5.0×105 Pa, so the stand cannot be used.
5.0×104 Pa5.0\times10^4\ \mathrm{Pa}5.0×104 Pa, so the stand can be used.
5.0×103 Pa5.0\times10^3\ \mathrm{Pa}5.0×103 Pa, so the stand can be used.
132 exam-style questions on Edexcel GCSE Physics 15.2 Pressure in fluids, covering 15.2.1 Atmospheric pressure and height, 15.2.2 Pressure in fluids, 15.2.3 Pressure, force and area, 15.2.4 Pressure and depth, 15.2.5 Pressure in liquids: depth and density, 15.2.6 Upthrust, and 15.2.7 Floating and sinking. Each one has a worked solution and a mark scheme showing where the marks go.