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Revision notes for Edexcel GCSE Physics Power and efficiency. Open the guide for explanations and worked examples. Written against the Edexcel GCSE Physics (1PH0) specification, so the content matches what's examinable rather than general Physics background.

Power and efficiency

What you'll learn

  • Why some mechanical processes become “wasteful” when they heat the surroundings.
  • What power means, and how to calculate it using energy and time.
  • Why 1 watt means 1 joule per second.
  • How to calculate efficiency as a decimal or percentage.

Starting point: energy transfers and work done

In this topic, you are still using the big idea that energy is transferred between stores. Energy is measured in joules (J).

When a force moves an object, the force does work. In physics, work done means energy has been transferred by a force.

Definition

Work done

Work done is the energy transferred when a force causes movement. Work done is measured in joules (J).

For this section, you often use the symbol EEE for energy transferred or work done.

Why mechanical processes can be wasteful

A mechanical process is any process involving movement and forces, such as gears turning, brakes slowing a bike, or a motor lifting a load.

Mechanical processes often involve friction. Friction is a force that opposes motion between surfaces in contact. When surfaces rub, energy is transferred to the thermal energy stores of the objects and surroundings, so their temperature increases.

Definition

Dissipated energy

Energy is dissipated when it spreads out into the surroundings, usually by heating, so it becomes less useful.

This does not mean energy has been destroyed. Energy is conserved, but it has been transferred in a way that is not useful for the job you wanted.

Key Idea

Wasteful energy transfers

Mechanical processes become wasteful when they cause a rise in temperature, because energy is dissipated by heating the surroundings instead of being transferred usefully.

Example

Explaining why brakes get hot

A cyclist brakes hard and the brake pads press against the wheel rim.

  1. The cyclist and bike initially have energy in their kinetic energy store because they are moving.
  2. Friction between the brake pads and wheel rim does work against the motion, reducing the kinetic energy store.
  3. Some of this energy is transferred to the thermal energy stores of the brake pads, wheel rim, and surrounding air, so their temperature increases.
  4. This energy has been dissipated to the surroundings, so the braking process is wasteful even though it is useful for slowing the bike.
Common Mistake

Wasted does not mean destroyed

Do not write that energy is “lost” without explaining where it goes. A better answer is: energy is dissipated to the surroundings by heating.

Power: how fast energy is transferred

Two machines might transfer the same amount of energy, but one might do it faster. That faster machine has a greater power.

Definition

Power

Power is the rate at which energy is transferred or the rate at which work is done.

A rate means “how much happens per second”. So power tells you how many joules of energy are transferred each second.

For Edexcel 1PH0, this is a recall equation:

P=EtP = \frac{E}{t}P=tE​

where:

  • PPP is power in watts (W)
  • EEE is energy transferred or work done in joules (J)
  • ttt is time taken in seconds (s)

You may also see it written as:

power=work donetime taken\text{power} = \frac{\text{work done}}{\text{time taken}}power=time takenwork done​
Key Idea

Same energy, shorter time

If the same energy is transferred in a shorter time, the power is greater.

Example

Comparing the power of two motors

Two motors each lift the same load, transferring 600 J of energy. Motor A takes 10 s. Motor B takes 4 s.

  1. Use the power equation for Motor A:

    P=Et=60010=60 WP = \frac{E}{t} = \frac{600}{10} = 60\ \text{W}P=tE​=10600​=60 W
  2. Use the same equation for Motor B:

    P=Et=6004=150 WP = \frac{E}{t} = \frac{600}{4} = 150\ \text{W}P=tE​=4600​=150 W
  3. Compare the values: 150 W is greater than 60 W, so Motor B is more powerful.

  4. This does not mean Motor B transferred more total energy; it transferred the same energy in less time.

Common Mistake

Power is not energy

Power and energy are different quantities. Energy is measured in joules (J). Power is measured in watts (W), which means joules per second.

The watt

The unit of power is the watt, symbol W.

Definition

Watt

One watt is equal to one joule of energy transferred per second: 1 W=1 J/s1\ \text{W} = 1\ \text{J/s}1 W=1 J/s.

So a 60 W lamp transfers 60 J of energy every second. A 2000 W kettle transfers 2000 J of energy every second.

Tip

Quick unit check

Because power is energy divided by time, watts must be the same as joules per second. If your answer is in J/s, that is also W.

Rearranging the power equation

You should be able to use the power equation in different forms:

P=EtP = \frac{E}{t}P=tE​

If you need energy:

E=PtE = P tE=Pt

If you need time:

t=EPt = \frac{E}{P}t=PE​
Example

Finding energy transferred by a kettle

A kettle has a power of 2200 W and is switched on for 180 s. Calculate the energy transferred.

  1. Choose the form of the equation that finds energy:

    E=PtE = P tE=Pt
  2. Substitute the values, using W for power and s for time:

    E=2200×180E = 2200 \times 180E=2200×180
  3. Calculate the energy transferred:

    E=396000 JE = 396000\ \text{J}E=396000 J
  4. In standard form, this is:

    E=3.96×105 JE = 3.96 \times 10^5\ \text{J}E=3.96×105 J

Investigating power in a practical

A common practical is to estimate your power when climbing stairs, doing step-ups, or lifting an object.

If you climb stairs, your useful energy transfer is the gain in gravitational potential energy. From earlier energy work:

Ep=mghE_p = mghEp​=mgh

where:

  • mmm is mass in kilograms (kg)
  • ggg is gravitational field strength, about 10 N/kg on Earth
  • hhh is height gained in metres (m)

Then you use:

P=EtP = \frac{E}{t}P=tE​
Example

Calculating power from climbing stairs

A student of mass 55 kg climbs a vertical height of 3.0 m in 4.5 s. Take g=10 N/kgg = 10\ \text{N/kg}g=10 N/kg. Calculate the student’s power.

  1. Find the useful energy transferred to the gravitational energy store:

    Ep=mgh=55×10×3.0=1650 JE_p = mgh = 55 \times 10 \times 3.0 = 1650\ \text{J}Ep​=mgh=55×10×3.0=1650 J
  2. Use the power equation:

    P=EtP = \frac{E}{t}P=tE​
  3. Substitute the energy and time:

    P=16504.5P = \frac{1650}{4.5}P=4.51650​
  4. Calculate the power:

    P≈367 WP \approx 367\ \text{W}P≈367 W
Tip

Practical accuracy

For a stair-climbing practical, measure the vertical height gained, not the distance walked along the stairs.

Efficiency: how much energy is useful?

No device transfers all its input energy usefully. Some energy is always dissipated to the surroundings, often by heating or sound.

Definition

Efficiency

Efficiency is the fraction of the total energy supplied to a device that is usefully transferred.

For Edexcel 1PH0, this is also a recall equation:

efficiency=useful energy transferred by the devicetotal energy supplied to the device\text{efficiency} = \frac{\text{useful energy transferred by the device}}{\text{total energy supplied to the device}}efficiency=total energy supplied to the deviceuseful energy transferred by the device​

Efficiency has no unit because it is a ratio. It can be written as a decimal or a percentage.

To convert a decimal efficiency to a percentage, multiply by 100.

A Sankey diagram shows energy transfers with arrows. The thicker the arrow, the larger the energy transfer.

Sankey diagram showing 100 J input split into 30 J useful output and 70 J wasted energy, giving 30% efficiency

Example

Calculating efficiency

A motor is supplied with 500 J of energy. It usefully transfers 125 J to lift a load. Calculate its efficiency as a decimal and as a percentage.

  1. Identify the useful energy and total energy:

    useful energy=125 J\text{useful energy} = 125\ \text{J}useful energy=125 J total energy=500 J\text{total energy} = 500\ \text{J}total energy=500 J
  2. Substitute into the efficiency equation:

    efficiency=125500\text{efficiency} = \frac{125}{500}efficiency=500125​
  3. Calculate the decimal efficiency:

    efficiency=0.25\text{efficiency} = 0.25efficiency=0.25
  4. Convert to a percentage:

    0.25×100=25%0.25 \times 100 = 25\%0.25×100=25%
Common Mistake

Dividing the wrong way round

Efficiency is useful energy divided by total energy supplied. If your efficiency is greater than 1, or greater than 100%, you have almost certainly put the numbers the wrong way round.

Improving efficiency

A device is more efficient if less energy is dissipated and more of the input energy is transferred usefully.

For mechanical systems, efficiency can often be improved by reducing friction. For example, machines may use lubrication, smoother surfaces, or better bearings.

Key Idea

Efficiency improvement

To improve efficiency, reduce unwanted energy transfers such as heating by friction or sound.

Be careful: improving efficiency does not always mean increasing power. A device can be powerful but inefficient if it transfers energy quickly but wastes a large fraction of it.

Exam technique

In the exam

  1. For power questions, check that energy is in joules and time is in seconds before using P=EtP = \frac{E}{t}P=tE​.
  2. For efficiency questions, always divide useful energy output by total energy input, then multiply by 100 if a percentage is required.
  3. When explaining wastefulness, say where the energy goes: it is dissipated to the surroundings by heating, often due to friction.
Self review

Check yourself

  • A machine transfers 900 J in 30 s. What is its power?
  • Why does friction make a mechanical process less efficient?
  • A device is supplied with 200 J and usefully transfers 80 J. What is its efficiency as a percentage?

Recap questions

Test yourself with 5 quick questions on this guide. Answer them all correctly to complete it.

Energy – forces doing work

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