A ball is released from rest. It passes point P after 0.50 s and point Q after 1.5 s.
Ignore air resistance and use g=10 m/s2g=10\ \mathrm{m/s^2}g=10 m/s2.
Use the equations a=v−ut\displaystyle a=\frac{v-u}{t}a=tv−u and v2−u2=2axv^2-u^2=2axv2−u2=2ax.
What is the distance between P and Q?
10 m10\ \mathrm{m}10 m
5.0 m5.0\ \mathrm{m}5.0 m
11 m11\ \mathrm{m}11 m
15 m15\ \mathrm{m}15 m