A cyclist rides down a straight hill.
The velocity of the cyclist increases from 4.0 m/s to 10 m/s over a distance of 42 m.
Calculate the acceleration of the cyclist.
Use the equation
v2−u2=2×a×xv^2 - u^2 = 2 \times a \times xv2−u2=2×a×x
Calculate the time taken for the cyclist to travel the 42 m.
At the bottom of the hill the cyclist brakes and stops from 10 m/s in a distance of 5.0 m.
Calculate the deceleration of the cyclist.