Moments, levers and gears

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Question 29
Easy

A mechanic uses a spanner to tighten a nut on a car engine.

A diagram showing a spanner fitted onto a hexagonal nut. A downward force F is applied at the end of the spanner handle, at a perpendicular distance d from the centre of the nut which acts as the pivot.

The force, FFF, applied by the mechanic is 12.0 N.

The moment of this force about the pivot is 3.6 N m.

Calculate the perpendicular distance, ddd, from the pivot to the line of action of the force. Use the equation:

moment of a force=force×distance \text{moment of a force} = \text{force} \times \text{distance} moment of a force=force×distance
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Moments, levers and gears Questions

  1. GCSE
  2. /Physics
  3. /Moments, levers and gears